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What is the perimeter of a rectangle with a length of 8 in and an area of 24 square inches?
KEY:
LENGTH=L
WIDTH=W
AREA=A
If the length of 1 side is 8 and the area is 24, we must find the other length. Since L*W=A we know that L=8 and A=24. So, the problem looks like this: 8*W=24. So, to reverse this, 24 divided by 8 = W. 24 divided by 8 = 3, so we know that L=8 and W=3. Perimeter = W+W+L+L so 8+8+3+3= 22. I hope that you understand the process. Please post something on my page if you need further help.
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