Q: What is the perimeter of a regular octagon with sides 4 mm long?

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21ft

Each side of the 48 inch perimeter is 6 inches long, therefore there are 48 / 6 = 8 of them. The figure is a regular octagon.

The perimeter of a regular hexagon is (6 x the length of one side).

35cm long since all the sides are the same

15 ft.

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It is: 8*4.6 = 36.8 cm

If each side is 1cm long then its perimeter is 8 times 1cm = 8 centimeters

112 inches, that is if all the sides are the same length .I think.

The perimeter is 8 times 12 = 96 inches

A regular octagon has 8 sides so if each side is 3 1/2 inches long then the perimeter is just 8*(3 1/2 inches) or 28 inches

A regular octagon has eight equal sides, but in general the sides of an octagon don't have to be equal as long as there are eight of them.

If the permiter of a regular octagon is 8z-16, then the length of each side would be the perimeter / 8 or 2z-2

It is a shape that has 8 sides but does not look like a regular octagon. As long as it has 8 sides it is an irregular octagon.

No. For a polygon to be regular all its sides must be of the same length.

the answer is 40 divided by 8, which is 5.

you add all the sides which is 8 sides. Another way instead of adding 12+12+12+12+12+12+12+12, you can multiply 12*8 which is ............

Each side is 56/8 (7).