112 inches, that is if all the sides are the same length .I think.
Yes, it can exist.
By joining all the vertices to the centre of the octagon, the apothem forms the height of the triangles with the side of the regular octagon as the base. This the area is 8 × area_triangles = 8 × ½ × side × apothem = 4 × side × apothem: Area_regular_octagon = 4 × side_length × apothem ≈ 4 × 4 in × 4.8 in = 76.8 in²
5 times 8.4= 42 inches
See if the Hexagon is regular, that is, if all the sides are equal then the perimeter is 12inches x 6 as there are 6 sides for an hexagon. Therfore the answer is 72 inches.
The perimeter of this rectangle is 30 inches.
If the octagon is not regular, the perimeter could have any value greater than 18 inches. If it is regular, then the perimeter is 8*18 = 144 inches.
An octagon is an eight-sided figure. If a regular octagon has a perimeter of 24 inches, then each side will be 24 / 8 = 3 inches.
8
77 in
providing it is a regular octagon then it is 8*4 = 32 inches
A regular octagon has 8 sides so if each side is 3 1/2 inches long then the perimeter is just 8*(3 1/2 inches) or 28 inches
Assuming that the perimeter of the regular octagon is 32 inches, and since it has 8 sides, then the length of one side of the figure is 32/8 or 4 inches.
You cannot. The perimeter alone does not provide enough information unless the octagon is regular and there is no valid reason to assume that it is.
The perimeter is 8 times 12 = 96 inches
The perimeter of an octagon that has one side of 2 inches is 16 inches.
1,472 inches (184 x 8 sides = 1,472).
8 sides each 9 inches: 6 feet