The perimeter of the rectangle is 2•66+2•32=196196/4(sides of a square)=49 cm
perimeter_of_square = 4 x side ⇒ side = perimeter ÷ 4 = 52 cm ÷ 4 = 13 cm area_of_square = side2 = (13 cm)2 = 169 cm2
Since it is a square, all four sides are the same. The side is sqrt(25 cm2) = 5 cm. The perimeter is 4 x 5 cm = 20 cm.
The perimeter is 20*sqrt(2) cm = 28.2843 cm
Consider a square with sides of length x cm whose area is x2 cm and perimeter is 4x cm. Next consider a rectangle with sides of 2x cm and x/2 cm. It area is 2x*x/2 = x2, the same as for the square. But its perimeter is 2*(2x+x/2) = 5x > perimeter of the square. Perimeter of 3x * x/3 = 62/3x cm. Perimeter of 100x * x/100 = 200.02x cm Perimeter of 1000000x * x/1000000 = 2000000.000002x cm. As you can see, it is possible to increase the perimeter without limit.
Area of a square = side^2 10,000 = side^2 100 = side Perimeter = 4(side) = 4 x 100 = 400 cm
The area of square is : 1936.0
The perimeter of the rectangle is 2•66+2•32=196196/4(sides of a square)=49 cm
perimeter of square = 4 * side side =32/4 =8 m area of square=side * side =8* 8 =64 cm ^ 2
To find the perimeter of a square with a diagonal of 16 cm, we first need to determine the side length of the square using the Pythagorean theorem. The diagonal of a square divides it into two right-angled triangles, with the diagonal being the hypotenuse. Using the formula a^2 + b^2 = c^2, where a and b are the two sides of the triangle and c is the hypotenuse, we can calculate that each side of the square is 8√2 cm. Since a square has four equal sides, the perimeter is 4 times the side length, giving us a perimeter of 32√2 cm.
perimeter_of_square = 4 x side ⇒ side = perimeter ÷ 4 = 52 cm ÷ 4 = 13 cm area_of_square = side2 = (13 cm)2 = 169 cm2
Area = (length of a side)2 = 81 square centimeters Perimeter = 4 x (length of a side) = 36 cm.
Since it is a square, all four sides are the same. The side is sqrt(25 cm2) = 5 cm. The perimeter is 4 x 5 cm = 20 cm.
The perimeter is 20*sqrt(2) cm = 28.2843 cm
1 Let each side be s 2 If: 0.5*s2*sin(60) = 692.820323 square cm 3 Then: s = square root of (692.820323*2)/sin(60) = 40 cm 4 Perimeter: 3*40 = 120 cm
Consider a square with sides of length x cm whose area is x2 cm and perimeter is 4x cm. Next consider a rectangle with sides of 2x cm and x/2 cm. It area is 2x*x/2 = x2, the same as for the square. But its perimeter is 2*(2x+x/2) = 5x > perimeter of the square. Perimeter of 3x * x/3 = 62/3x cm. Perimeter of 100x * x/100 = 200.02x cm Perimeter of 1000000x * x/1000000 = 2000000.000002x cm. As you can see, it is possible to increase the perimeter without limit.
Area of square= side*sideIf you mean by "length of the square" one side of the square, then the area is 16 cm^2 (If you mean by "length of the square" it's perimeter, then you have to get it'a side from that data:Perimeter of squre=4*side -> side = (Perimeter of square)/4 then you get one side and you can calculate the area from that...)