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To find the perimeter of a square with a diagonal of 16 cm, we first need to determine the side length of the square using the Pythagorean theorem. The diagonal of a square divides it into two right-angled triangles, with the diagonal being the hypotenuse. Using the formula a^2 + b^2 = c^2, where a and b are the two sides of the triangle and c is the hypotenuse, we can calculate that each side of the square is 8√2 cm. Since a square has four equal sides, the perimeter is 4 times the side length, giving us a perimeter of 32√2 cm.

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1mo ago
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14y ago

The perimeter of this square is 45.25 cm

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Q: What is the perimeter of a square whose one diagonal is 16cm?
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The perimeter of a rhombus is 40cm and the length of one diagonal is 16cm find the length of the other diagonal?

The length of the other diagonal works out as 12cm


What is the perimeter of a square with 16cm as the side?

IF 16cm is EACH side, the answer is four (sides) times 16cm... so that's 64 cm.


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The area of square is : 256.0


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Any type of polygon can have a perimeter of 16 cm. There is no special name for polygons whose perimeter is 16 cm.


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anything imaginary but a real shape would be a square or rectangle.


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4m x 4m works


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16cm (4 sides x 4 = 16)


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3 + 3 + 5 + 5 = 16cm


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The perimeter is all of the sides added together. So 4+4+4+4 is 16. The perimeter is 16cm.


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What is the perimeter of a square with each area of 16 cm squared?

To find the perimeter of a square, you first need to work out the side length. The area of a square is L2 where L is the side length. The area of the square in the question is 16cm2 so L is the square root of 16, or 4. To get the perimeter of the square, we simply multiply the side length by 4. In this case 4x4=16, so the perimeter of the square is 16cm.