To find the perimeter of a square with a diagonal of 16 cm, we first need to determine the side length of the square using the Pythagorean theorem. The diagonal of a square divides it into two right-angled triangles, with the diagonal being the hypotenuse. Using the formula a^2 + b^2 = c^2, where a and b are the two sides of the triangle and c is the hypotenuse, we can calculate that each side of the square is 8√2 cm. Since a square has four equal sides, the perimeter is 4 times the side length, giving us a perimeter of 32√2 cm.
The length of the other diagonal works out as 12cm
The area of square is : 256.0
16cm (4 sides x 4 = 16)
3 + 3 + 5 + 5 = 16cm
The greatest area that a rectangle can have is, in fact, attained when it is a square. A square with perimeter of 16 cm must have sides of 4 cm and so an area of 4*4 = 16 cm2.
The length of the other diagonal works out as 12cm
IF 16cm is EACH side, the answer is four (sides) times 16cm... so that's 64 cm.
The area of square is : 256.0
Any type of polygon can have a perimeter of 16 cm. There is no special name for polygons whose perimeter is 16 cm.
anything imaginary but a real shape would be a square or rectangle.
4m x 4m works
16cm (4 sides x 4 = 16)
3 + 3 + 5 + 5 = 16cm
Well, honey, the perimeter of a rectangle is calculated by adding up all the sides. So for a rectangle that's 6cm by 2cm, you just do 6 + 6 + 2 + 2 which equals 16cm. There you go, darling, hope that helps!
The perimeter is all of the sides added together. So 4+4+4+4 is 16. The perimeter is 16cm.
16 cm*16 cm =256 cm2
16cm.