The lengths of two sides are not enough to determine the perimeter of a triangle: Either the third side or else the angle between the two given sides is also needed. If two of the sides are 10m and 25m, then the third side can be anything between 15m and 35m, and the perimeter can be anything between 45m and 70m.
The Perimeter of a rectangle is 2(L+W). Let x represent the Width and x+5 represent the Length: 150 = 2(x+x+5) 150 = 2(2x+5) 150 = 4x+10 140 = 4x 35 = x The Width is 35m and the Length is 40m (35+5).
It is: (pi*17.5)+35 = 90 meters rounded to nearest whole number
3500mm=3.5 m.1000mm= 1 meter=100 cm.
18.5 metres are left.
Area = 35*35 = 1225 square m With the dimensions given it is not a rectangle but it is a square <><><><> Above is correct- but squares are also rectangles.
The Alexander from Hull Great Britain was 114ft (35m) in length.
The lengths of two sides are not enough to determine the perimeter of a triangle: Either the third side or else the angle between the two given sides is also needed. If two of the sides are 10m and 25m, then the third side can be anything between 15m and 35m, and the perimeter can be anything between 45m and 70m.
The Perimeter of a rectangle is 2(L+W). Let x represent the Width and x+5 represent the Length: 150 = 2(x+x+5) 150 = 2(2x+5) 150 = 4x+10 140 = 4x 35 = x The Width is 35m and the Length is 40m (35+5).
It is: (pi*17.5)+35 = 90 meters rounded to nearest whole number
well first you form two equations: let the width = x and the length = y now as the perimeter is given and the shape is a rectangle, you know that the two opposite sides are equal, hence: 2x + 2y = 702 and secondly, you are told that the length is 35m longer than the width, hence: y = x + 35 now you simultaneously equate these two equations by first substituting y = x + 35 into the first equation. 2x + 2(x+35) = 702 2x + 2x + 70 = 702 4x = 632 x = 158 now substitute x = 158 into the second equation y = 158 + 35 y = 193 therefore, the width = 158m and the length = 193m
3500mm=3.5 m.1000mm= 1 meter=100 cm.
I you add lots of lengths, you get a length, not an area.
Field is square ===> full perimeter travel time is 4 x (one side travel time) = 4 x 40 = 160sec = 2min 40sec 2min 20sec is 20sec short of the full perimeter = 1/2 of one-side travel time = 5 meters' travel time
The distance traveled would be 135m (100m + 35m) since it's the total length of the path you walked. The displacement would be 65m forward because it's the difference between your final position and your initial position.
500 ft. tall and 30 ft. wide
35M.