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The formula is Length x Width E.G. the rectangle is 2 metres long and 1 metre wide that would be: 2x1=2
2x1=2
( 3x10) + ( 2x1) = 32
CCCLXVII (100x3 + 50 + 10 + 5 + 2x1)
This is clearer if you use fractional powers, at least for the intermediate steps. The fourth root of 32x2y2 is (32x2y2)1/4, or 31/2x1/2y1/2. In other words, the square root of 3xy.
it doesnt have an inverse since only square matrices have an inverse
The determinant is only defined for square matrices.
To answer this simply try a few out for yourself. In a 2x1 cm rectangle, the area is 2 cm squared and the perimeter is 6 cm In a 12x10 rectangle, the area is 120 cm squared and the perimeter is 44 cm. In some cases, the perimeter is larger and in others it is smaller. To answer your question, no, the perimeter of a rectangle is NOT always greater than its area.
The standard size of a checker square is 1x1 square inches. It is not well standardized in commercially sold sets. Surviving purposes, there are 'pocket editions' that a square has a lesser area than 1/2x1/2 square inches.
2
The formula is Length x Width E.G. the rectangle is 2 metres long and 1 metre wide that would be: 2x1=2
22 + .056
True
2x (1+3)=(2x1+(2x3)
1x2 2x1
2x1=2
( 3x10) + ( 2x1) = 32