2x (1+3)=(2x1+(2x3)
What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).
30
1
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
A determinant is defined only for square matrices, so a 2x3 matrix does not have a determinant.Determinants are defined only for square matrices, so a 2x3 matrix does not have a determinant.
2, 4, 6, 8 (2x1, 2x2, 2x3, 2x4)
2x1 is 2 2x2 is 4 2x3 is 6 2x4 is 8 2x5 is 10 2x6 is 12
you would get an even number; 2x1=2 2x3=6 2x5=10
The following are examples of expressions:2x3 + 72 × y + 52 + 6 × (4 - 2)z + 3 × (8 - z)
The CALL instruction uses 18 clock cycles. 3x3 fetch, 2x3 store, 1x1 decode, 2x1 decrement.
1x6, 2x3
Maximize z = 6x1 - 2x2+ 3x3 subject to 2x1 - x2 + 2x3 ≤ 2, x1+ 4x3 ≤ 4, x1, x2 , x3 ≥ 0.
algebra: 5[2x3(22-13)+3] mathematical: 5x2
2+4, 10-4, 2x3, 1+1x5.the list can just go on.
The order of steps you take in a math problem Parentheses, Exponents, Multiplication, Division, Addition, Subtraction For Example: (2x3)+20-2x5, if you follow pemdas the answer is:16
no.. prime numbers are numbers that can only have two factors (which are that number and one) to get that number. Ex: 2, because only 2x1=2, 5 because only 5x1=5, but NOT 6 because 6x1=1 AND 2x3=6
No. 2 times any whole (non-fraction) number will never be odd. 2x1=2 2x2=4 2x3=6 2x4=8 and so on. Only if it is a fraction can it become an odd number (ex 2x1.5=3)