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Line segment: (3, 5) and (7, 7)

Midpoint: (3+7)/2, (5+7)/2 = (5, 6)

Slope or gradient: (7-5)/(7-3) = 1/2

Perpendicular slope = -2

Equation: y -6 = -2(x-5) => y = -2x+10+6 => y = -2x+16

So the perpendicular bisector equation is y = -2x+16

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Q: What is the perpendicular bisector equation meeting the line segment of 3 5 and 7 7?
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