Chord equation: y = x+5
Circle equation: x^2 +4x +y^2 -18y +59 = 0
Chord end points: (-1, 4) and (3, 8)
Chord midpoint: (1, 6)
Perpendicular slope: -1
Perpendicular bisector equation: y-6 = -1(x-1) => y = -x+7
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
If: y = 5x +10 and y = x^2 +4 Then: x^2 +4 = 5x +10 Transposing terms: x^2 -5x -6 = 0 Factorizing the above: (x-6)(X+1) = 0 meaning x = 6 or x = -1 Therefore by substitution endpoints of the line are at: (6, 40) and (-1, 5) Midpoint of line: (2.5, 22.5) Slope of line: 5 Perpendicular slope: -1/5 Perpendicular bisector equation: y-22.5 = -1/5(x-2.25) => 5y = -x+114.75 Perpendicular bisector equation in its general form: x+5y-114.75 = 0
Points: (4, 1) and (0, 4) Slope: -3/4 Equation: 4y = -3x+16 Perpendicular slope: 4/3 Perpendicular equation: 3y = 4x-13 Both equations meet at: (4, 1) from (7, 5) at right angles Perpendicular distance: square root of [(4-7)squared+(1-5)squared)] = 5 units
no
Equation: 7x+13-y = 0 => y = 7x+13Slope: 7Perpendicular slope: -1/7Perpendicular equation: 7y = -x+37Both equations intersect at: (-1.08, 5.44)Distance: square root of [(-1.08-2)squared+(5.44-5)squared)] = 3.111 to 3 d.p.
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
If: y = 5x +10 and y = x^2 +4 Then: x^2 +4 = 5x +10 Transposing terms: x^2 -5x -6 = 0 Factorizing the above: (x-6)(X+1) = 0 meaning x = 6 or x = -1 Therefore by substitution endpoints of the line are at: (6, 40) and (-1, 5) Midpoint of line: (2.5, 22.5) Slope of line: 5 Perpendicular slope: -1/5 Perpendicular bisector equation: y-22.5 = -1/5(x-2.25) => 5y = -x+114.75 Perpendicular bisector equation in its general form: x+5y-114.75 = 0
Points: (4, 1) and (0, 4) Slope: -3/4 Equation: 4y = -3x+16 Perpendicular slope: 4/3 Perpendicular equation: 3y = 4x-13 Both equations meet at: (4, 1) from (7, 5) at right angles Perpendicular distance: square root of [(4-7)squared+(1-5)squared)] = 5 units
no
Equation: 7x+13-y = 0 => y = 7x+13Slope: 7Perpendicular slope: -1/7Perpendicular equation: 7y = -x+37Both equations intersect at: (-1.08, 5.44)Distance: square root of [(-1.08-2)squared+(5.44-5)squared)] = 3.111 to 3 d.p.
A quadratic equation.
the name is squared equation
The "E" in Einstein's equation (E=mc^2) represents energy. This equation states that energy (E) is equal to mass (m) times the speed of light (c) squared, showing the relationship between mass and energy.
Sin squared, cos squared...you removed the x in the equation.
No, It's a a quadratic equation because you have X squared.
11
A squared plus b squared equils c squared