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What does a perpendicular bisector do?
A perpendicular bisector [for a given line segment] is a line that meets it at 90 degrees and divides it into two halves.
What is the perpendicular bisector equation that meets the line segment of 7 3 and -6 1 showing work in addition to the answer?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular bisector equation: y-2 = -13/2(x-0.5) => 2y = -13x+10.5
What is the perpendicular bisector equation that meets the line sgment of -1 -6 and 5 -8 on the Cartesian plane showing work?
To find the perpendicular bisector of the line segment connecting the points (-1, -6) and (5, -8), we first calculate the midpoint of the segment. The midpoint (M) is given by: [ M = \left( \frac{-1 + 5}{2}, \frac{-6 + (-8)}{2} \right) = \left( 2, -7 \right). ] Next, we find the slope of the line segment, which is [ \text{slope} = \frac{-8 - (-6)}{5 - (-1)} = \frac{-2}{6} = -\frac{1}{3}. ] The slope of the perpendicular bisector is the negative reciprocal, which is 3. Using the point-slope form of a line, the equation of the perpendicular bisector is: [ y + 7 = 3(x - 2). ] This simplifies to: [ y = 3x - 13. ]
What is the perpendicular bisector equation that meets the points of 7 3 and -6 1 on the Cartesian plane?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular equation: y-2 =-13/2(x-0.5) => 2y-4 = -13x+6.5 => 2y = -13x+10.5 Therefore the perpendicular bisector equation is: 2y = -13x+10.5
What is the perpendicular line segment construction?
The perpendicular line segment construction involves creating a line segment that meets another line at a right angle (90 degrees). This is typically done using a compass and straightedge. First, a point is marked on the line where the perpendicular will intersect. Then, arcs are drawn from this point to establish two points equidistant from it, allowing the straightedge to connect these points, forming a perpendicular line.
What does a perpendicular bisector do?
A perpendicular bisector [for a given line segment] is a line that meets it at 90 degrees and divides it into two halves.
What is the perpendicular bisector equation that meets the line segment of -2 2 and 6 4 at its midpoint showing work?
Points: (-2, 2) and (6, 4) Midpoint: (2, 3) Slope: 1/4 Perpendicular slope: -4 Perpendicular bisector equation: y-3 = -4(x-2) => y = -4x+11
What is the perpendicular bisector equation that meets the line segment of 7 3 and -6 1 showing work in addition to the answer?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular bisector equation: y-2 = -13/2(x-0.5) => 2y = -13x+10.5
What is prependicular bisector?
A perpendicular bisector is a line which cuts a line segment into two equal parts at 90°.
What is the perpendicular bisector equation that meets the points of 7 3 and -6 1 on the Cartesian plane?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular equation: y-2 =-13/2(x-0.5) => 2y-4 = -13x+6.5 => 2y = -13x+10.5 Therefore the perpendicular bisector equation is: 2y = -13x+10.5
What is the perpendicular bisector equation in its general form that meets the line containing the points 7 3 and -6 1 showing work?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular equation: y-2 = -13/2(x-0.5) => 2y = -13x+10.5 Perpendicular bisector equation in its general form: 26x+4y-21 = 0
What is the perpendicular bisector equation that meets the line whose end points are at -2 plus 5 and -8 -3?
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Perpendicular bisector equation: y-1 = -3/4(x--5) => 4y-4 = -3x-15 => 4y = -3x-11
What is the perpendicular bisector equation that meets the line of 7 3 and -6 1 on the Cartesian plane?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular equation: y-2 = -13/2(x-0.5 => 2y = -13x+10.5
What is the perpendicular bisector equation that meets the line 13 19 and 23 17 at midpoint on the Cartesian plane showing all aspects of work with answer?
Points: (13, 19) and (23, 17) Midpoint: (18, 18) Slope: -1/5 Perpendicular slope: 5 Perpendicular equation: y-18 = 5(x-18) => y = 5x-72
What is a perpendicular bisector?
a line that cuts through parallel lines so that each angle created has a measure of 90degrees* * * * *No. That is a transversal.A perpendicular bisector [for a given line segment] is a line that meets it at 90 degrees and divides it into two halves.It is 2 lines that intersect each other at 90 degrees
What is the perpendicular bisector equation that meets the line segment of -1 -6 and 5 -8 on the Cartesian plane showing work?
Suppose P = (-1, -6) and Q = (5, -8) Then gradient of PQ = (-8 --6)/(5 --1) = -2/6 = -1/3 Therefore gradient of the perp bisector = 3 [because product of gradients = -1] Mid point of PQ = [(-1+5)/2, (-6-8)/2] = (2, -7) Eqn of perp bisector = y + 7 = 3*(x - 2) or 3x - y - 13 = 0
What is the shortest segment from a point to line?
A line that is perpendicular to the given line and passes through the given point.
