If you mean the point of (2, 5) then the 1st step is to move 2 units to the right of the origin then move 5 units up to locate the given point.
-3 to 2 is +5 units so move another +5 units to +7 -4 to -1 is +3 units so move another +3 units to +2 So the other end point is (7,2)
Which point is 5 units from (-6, 2)? A. (-6, -7) B. (-6, -3) C. (1, 2) D. (11, 2) (The real question)
On the 2-dimensional coordinate plane it is a point that is on the y-axis, two units of length away from the origin.
-4
yes it 37oF
If you we're at the point (8,-2) and you went 5 units right and 2 units up, you'd be at (13,0).
(-4,-2)
None. If a point is 2 units from 'A' and equidistant from 'A' and 'B', then it also has to be2 units from 'B'.But the shortest distance between 'A' and 'B' is 6 units, and the point on that line that's equidistantfrom both of them is the point in the middle, which is 3 units from each.So a point equidistant from 'A' and 'B' must be 3 or more units from each one. 2 units won't do it.
If you mean the point of (2, 5) then the 1st step is to move 2 units to the right of the origin then move 5 units up to locate the given point.
(2,1)
-3 to 2 is +5 units so move another +5 units to +7 -4 to -1 is +3 units so move another +3 units to +2 So the other end point is (7,2)
By going left 3 units and down 4 units.
Which point is 5 units from (-6, 2)? A. (-6, -7) B. (-6, -3) C. (1, 2) D. (11, 2) (The real question)
On the 2-dimensional coordinate plane it is a point that is on the y-axis, two units of length away from the origin.
-4
You don't necessarily do so!