None. If a point is 2 units from 'A' and equidistant from 'A' and 'B', then it also has to be
2 units from 'B'.
But the shortest distance between 'A' and 'B' is 6 units, and the point on that line that's equidistant
from both of them is the point in the middle, which is 3 units from each.
So a point equidistant from 'A' and 'B' must be 3 or more units from each one. 2 units won't do it.
Points: (-6, 1) and (-2, -2) Distance: 5 units
The distance between the points of (4, 3) and (0, 3) is 4 units
28
If you mean endpoints (-1, -3) and (11, -8) then by using the distance formula the length between the points is 13 units
That depends on the direction of the point in reference to the original coordinate. If the new point is 5 units to the right of (1,3), then the point is (6,3). If the point is 5 units left of (1,3), then the point is (-4,3). And so on.
zero Half the distance between them would be 4 units; so 3 units from P would not be close enough to Q to be equidistant.
4
There are two numbers that are 10 units from zero on the number line: 10 and -10. These two points are equidistant from zero, each being exactly 10 units away.
Any metric or non-metric units can be represented by points on the plotted line.
12 points per model, 5-20 units per group.
a and e a+
Points: (-6, 1) and (-2, -2) Distance: 5 units
Points: (3, -4) and (3, 3) Distance: 7 units
Points: (-5, -2) and (3, 13)Distance works out as 17 units
Energy
Then one point is 20 units away from the other.
The distance between the points of (4, 3) and (0, 3) is 4 units