You have two simultaneous equations; solve them:
As in the second equation the x coefficient is twice that in the first equation, subtract twice the first equation from the second and solve for y; {2}-2×{1}:
(4x - 2×2x) + (5y - 2×-3y) = 1 - 2×-5
→ (4x - 4x) + (5y - -6y) = 1 - -10
→ 5y + 6y = 1 + 10
→ 11y = 11
→ y = 1
Now substitute back into one of the equations (say {2}):
4x + 5y = 1
→ 4x + 5×1 = 1
→ 4x = 1 - 5 = -4
→ x = -1
Now substitute the values for x and y back into the other equation ({1}) as a check:
2x - 3y = 2×-1 - 3×1 = -2 - 3 = -5 as required.
Thus the lines intersect at the point (-1, 1).
Points of intersection work out as: (3, 4) and (-1, -2)
On the Cartesian plane the y axis crosses the x axis at the point of origin which is at (0, 0)
Cartesian plane
The cartesian coordinates are plotted on the cartesian plane
The two solutions are (x, y) = (-0.5, -sqrt(3.5)) and (-0.5, sqrt(3.5))
It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.
origin
Points of intersection work out as: (3, 4) and (-1, -2)
On the Cartesian plane the y axis crosses the x axis at the point of origin which is at (0, 0)
This is a point on the cartesian coordinate plane... (10,13)
Quadrant.
It is at the origin whose coordinates are at (0, 0) on the Cartesian plane
Cartesian plane
The cartesian coordinates are plotted on the cartesian plane
The two solutions are (x, y) = (-0.5, -sqrt(3.5)) and (-0.5, sqrt(3.5))
what are the parts of the Cartesian plane ?
The xy or Cartesian or coordinate plane.