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Find the equation of the line perpendicular to -9x 2y-3 that contains the poins 3-1?
"http://wiki.answers.com/Q/Find_the_equation_of_the_line_perpendicular_to_-9x_2y-3_that_contains_the_poins_3-1"
What is the equation of a line that is perpendicular to and passes through the point (4 6)?
That would depend on its slope which has not been given.
What is the equation of the line passing through the point -2 -3 and is perpendicular to the line 4x plus 3y -5 equals 0?
Perpendicular equation: 4x +3y -5 = 0 Perpendicular slope: -4/3 Slope of line: 3/4 Point of line: (-2, -3) Equation of line: y - -3=3/4(x - -2) => 4y - -12=3x - -6 => 4y = 3x -6 Therefore the equation of the line is: 4y = 3x -6 or 3x -4y -6 = 0
Can you write the equation of a line with one point on the line?
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
What equation of the line that contains the point 1 -1 and 2 -2?
Choose the equation of the line that contains the points (1, -1) and (2, -2).
What is the equation of a line that contains the point (21) and is perpendicular to the line y 3x 4?
If you mean the point of (2, 1) and the line y = 3x+4 Then the perpendicular slope is -1/3 and its equation works out as 3y = -x+5
Find the equation of the line perpendicular to -9x 2y-3 that contains the poins 3-1?
"http://wiki.answers.com/Q/Find_the_equation_of_the_line_perpendicular_to_-9x_2y-3_that_contains_the_poins_3-1"
What is the equation of a line that is perpendicular to and passes through the point (4 6)?
That would depend on its slope which has not been given.
What is the equation of a line that passes through the point 0 -3 and is perpendicular to a line with a slope of 4?
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
What is the equation of the line passing through the point -2 -3 and is perpendicular to the line 4x plus 3y -5 equals 0?
Perpendicular equation: 4x +3y -5 = 0 Perpendicular slope: -4/3 Slope of line: 3/4 Point of line: (-2, -3) Equation of line: y - -3=3/4(x - -2) => 4y - -12=3x - -6 => 4y = 3x -6 Therefore the equation of the line is: 4y = 3x -6 or 3x -4y -6 = 0
What is perpendicular to the line 3x plus y equals 2?
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
Can you write the equation of a line with one point on the line?
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
What is the equation of the line perpendicular to y equals 3x minus 7 that contains points 6 and 8?
In the Cartesian plane, each point has two coordinates. Point 6 and point 8 are not sufficiently uniquely defined.
What equation has a graph perpendicular to y equals 2x-3?
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What equation of the line that contains the point 1 -1 and 2 -2?
Choose the equation of the line that contains the points (1, -1) and (2, -2).
What equation describes a line that passes through the point (-14) and is perpendicular to the line 4x-3y-9?
If you mean point (-1, 4) and equation of 4x-3y = -9 then y = 4/3x+3 Slope of equation: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13
How do I write the equation of the line that passes through the given point and is perpendicular to the given line Write the answer in slope-intercept form?
The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.
