When it is a line through the origin.
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
Given a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
Slope Intercept form is meant for a line, so if you know the slope m in the equation y=mx+b then with a given point say (3,4) and say the slope of the line was 2 then the equation would read y=2x+4.
no it is different
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Point: (-6, -2) Slope: 5 Equation: y = 5x+28
When it is a line through the origin.
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Point: (1, 4) Slope: -3 Equation: y = -3x+7
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
You use point-slope form to find the equation of a line if you only have a point and a slope or if you are just given two point. Usually you will convert point-slope form to slope-intercept form to make it easier to use.
Slope: -3 Point: (4, -5) Equation: y = -3x+7
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
Given a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7