If you notice, 8x + 4 = 4(2x + 1), but there is an odd coefficient for x2, so there is guaranteed to be some remainder (that is 8x + 4 is not a factor of the polynomial): (24x3 - 5x2 - 48x - 8) ÷ (8x + 4) = 3x2 - 2x - 5 - (x2 - 12)/(8x + 4)
(5x - 7)(x + 3)
The only factor is 2. 2*(t3 + 2t2 + 4x)
32
(x - 4)(x - 4)
If you notice, 8x + 4 = 4(2x + 1), but there is an odd coefficient for x2, so there is guaranteed to be some remainder (that is 8x + 4 is not a factor of the polynomial): (24x3 - 5x2 - 48x - 8) ÷ (8x + 4) = 3x2 - 2x - 5 - (x2 - 12)/(8x + 4)
(5x - 7)(x + 3)
The only factor is 2. 2*(t3 + 2t2 + 4x)
(x-4)(x-4)
32
(x - 4)(x - 4)
(x + 6)(x + 2)
It is 4x^2 + 10x - 1
x² + 8x + 15 = (x + 5)(x + 3)
2(4x - 3)
5x2-8x-4
(x - 2)(x - 2)(x - 1)