Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y2 of (x + y)2.
There is no operator between 3x3 and x2 (which I assume are 3x-cubed and x-squared).
The square roots of any positive real number are a positive and a negative real number. The square roots of any negative real number are a positive and a negative imaginary number. The square roots of any imaginary number or any complex number are two complex numbers.
They are called real numbers. Negative square roots must be complex numbers.
If the discriminant is negative, the roots will be two unreal complex conjugates. If the discriminate is positive the roots will be real.
A number like 20 has two square roots: one positive and one negative. Specifically, the square roots of 20 are √20 and -√20. In general, any positive real number has two square roots, while zero has one, and negative numbers have no real square roots.
Assuming that you mean the nth. root: two - a negative and a positive root.
If "a" is positive, it will have two fourth roots, one will be positive and one will be negative it will have one fifth root, which will be positive. If "a" is negative, it will have one fourth root, which will be negative. it will have one fifth root, which will be negative.
The square roots of any positive real number are a positive and a negative real number. The square roots of any negative real number are a positive and a negative imaginary number. The square roots of any imaginary number or any complex number are two complex numbers.
there is no cube roots in negative
there are no real answers to an even root (2,4,6,8) of any negative number. the innovation of i allows you to find the unreal answers. i= the fourth root of positive 16 is 2. so, the roots of -16 are positive and negative 2i. post script: you cannot have a real even root of a negative because a negative multiplied by a negative turns into a positive.
Yes. If the discriminant (of a quadratic equation) is...Positive: There are two real roots.Zero: There is a single "double" root. ("Double" means that if you factor, you will have a repeated factor.)Negative: There are two complex roots (and no real roots).
They are called real numbers. Negative square roots must be complex numbers.
If the discriminant is negative, the roots will be two unreal complex conjugates. If the discriminate is positive the roots will be real.
A number like 20 has two square roots: one positive and one negative. Specifically, the square roots of 20 are √20 and -√20. In general, any positive real number has two square roots, while zero has one, and negative numbers have no real square roots.
Well, darling, the real square roots of 0.0049 are +0.07 and -0.07. It's simple math, really. Just remember, a negative times a negative gives you a positive, and a positive times a positive also gives you a positive. Math can be sassy too, you know!
Any real number - positive or negative - has exactly one real cube root. Any real number (except zero) has three cubic roots in the complex numbers; but only one of them is real.
Assuming that you mean the nth. root: two - a negative and a positive root.
Negative numbers do not have "real number" square roots.However, they will have two roots (when using imaginary numbers) as do other numbers, where a root including i(square root of -1) is positive or negative.