Choose a nonzero integer for n to show -n can be evaluated as a positive number?
1,560 is.
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
10
Positive exponents: an = a*a*a*...*a where there are n (>0) lots of a. Negative exponents: a-n = 1/(a*a*a*...*a) where there are n (>0) lots of a.
Let's use N to represent any number.N x N = NN x -N = -N-N x -N = NSo the rules are:A positive integer times a positive integer will be a positive integerA positive integer times a negative integer will be a negative integerA negative integer times a negative integer will be a positive integer.
No, there is not. Given any positive integer n, n+1 is also a positive integer and it is larger.
Choose a nonzero integer for n to show -n can be evaluated as a positive number?
What a delightful little problemette ! It has to be the sum of the integers from 1 to 'n' . If 'n' is an even number, then that's n/2 times (n+1), (as in the young Gauss).
1,560 is.
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
Since n is positive, |n| = n, so you have 2n - n = n. The difference is n.
They are all the members of the set { n } where 1 ≤ n ≤ 180 . If we require that (n) = the greatest integer in (n), then there are 180 members in the set. If that condition is not required, then there are an infinite number of them.
605
n=27
10
No, it cannot.Consider a polygon which has n vertices, where n is an integer greater than or equal to 3.The sum of the interior angles of such a polygon is 180*(n - 2) degrees.Since n is an integer, (n - 2) must be an integer and so 180 must be a factor of the sum of the angles.180 does not divide 4300 and so it cannot be the sum of interior angles.It is, of course possible for a polygonal shape on a curved surface to have an angle sum of 4300 degrees, but such a shape would not be a polygon.