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Q: What is the difference of a positive integer n and twice its absolute value?

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The integers are 14 and 7.

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One (negative) is preceded by a - sign and the other (positive) is not. Negative integers have values less than zero, whereas positive integers have values greater than zero. If a positive and negative integer are made up of the same digits and in the same order (e.g., 2 and -2, or 896 and -896), then when added together they will equal zero. If, however, one is subtracted from the other, then they will equal twice the number from which the other is subtracted.

no one wants to know the answer. its freaking math

Let one integer be n, then the other is 2n + 3 and n(2n + 3) = 90; solve this last equation for n: n(2n + 3) = 90 ⇒ 2n2 + 3n - 90 = 0 ⇒ (2n + 15)(n - 6) = 0 ⇒ n = 6 or n = -7.5 As n must be a (positive) integer, the solution n = -7.5 can be ignored, leaving n = 6, giving 2n + 3 = 15. Thus the two positive integers are 6 and 15.

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An unsigned integer cannot be negative. It has a maximum positive value twice that of a signed integer. Max signed: 128 Max signed: 256 I could be off by one there, though.

An LCD is a positive integer. But any integer can can be expressed as a fraction : as the same number divided by 1. Or twice the number divided by 2, etc.

The integers are 14 and 7.

The two integers are 7 and 14. 7 x 14 = 98.

An equation with absolute values instead of simple variables has twice as many solutions as an otherwise identical equation with simple variables, because every absolute value has both a negative and a positive counterpart.

You multiply an integer by itself twice or multiply 1 by an integer three times.

x = 3 + 2y

In each case the difference is twice the absolute value and the absolute value of -3 and +3 (which is 3) is smaller than the absolute value of -4 and +4 (which is 4).

It can be: 2x-25 or 25-2x or maybe the absolute value of (2x-25).

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find the sum of 2 and 2

9 and 10 9 + 2(10) = 29

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