Presumably you are asking what the chance of rolling AT LEAST one 2 is. To do this calculation we first work out the probability of NOT rolling a 2, which is 1/6.
We then calculate the probability of NOT rolling ANY 2 in 500 rolls. That is 1/6 to the power of 500.
So now that we have the probability of it NOT happening, we subtract that number from 1 to get the probability of it happening.
Pr(x) = 1 - 1/6^500
The answer is so close to 1 that it's not worth writing out decimally. Basically 0.999999... with almost 400 nines. It's virtually guaranteed that you will get at least one 2 in 500 rolls.
If your question was instead what is the chance of getting ONLY one 2 out of 500 rolls then the answer is basically the opposite - the answer is almost zero.
If you keep rolling the die, then the probability of rolling a 6 and then a 1 on consecutive rolls is 1.The probability is 1/36 for the first two throws.
The probability of rolling an 8 is Zero.
A cube has six sides. Therefore this is impossible.
Prob(No sixes in 6 rolls) = [Prob(Not a six in a roll)]6 = (5/6)6 = 0.3349
1/2!
If you keep rolling the die, then the probability of rolling a 6 and then a 1 on consecutive rolls is 1.The probability is 1/36 for the first two throws.
The probability of rolling an 8 is Zero.
One roll of one normal cube: the answer is 0.
A cube has six sides. Therefore this is impossible.
Prob(No sixes in 6 rolls) = [Prob(Not a six in a roll)]6 = (5/6)6 = 0.3349
1/2!
1/6 or 1 in 6 :)
1 in 6 = rolling a 2 5 in 6 = not rolling a 2
It is 1/36.
The probability of not rolling it ever is 0.For n rolls it is (5/6)n sofor 10 rolls it is 0.1615for 20 rolls it is 2.608*10-2for 100 rolls it is 1.207*10-8 and so on.
The probability is 0.
On a single roll, it is 1/6