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The prime factorization of 333 with exponents is 32 x 371

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What is the prime factor of 333 using exponents?

To find the prime factorization of 333 using exponents, we first need to break it down into its prime factors. 333 can be factored as 3 x 3 x 37. Writing this in exponential form, we get 3^2 x 37. Therefore, the prime factorization of 333 using exponents is 3^2 x 37.


What is the prime factorization of 333 in exponents?

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The prime factorization for 112 using exponents is: 24 x 7


What is the prime factorization of 112 using exponents?

Since '112' is an even number, you divide by '2' , the smallest prime number. 2)112 2)56 2)28 2)14 7)7 = 1 NB Reduce by using prime number denominators until you reach '1'. Hence 112 = 2x2x2x2x7 = 2^(4) X 7^(1)


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The prime factorization, using exponents, of 160 is: 25 x 5


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