2 and 118.
The numbers that are divisible by 118 are infinite. Four of them are: 118, 236, 354, 472.Itself and any of its multiples
composite
118 is divisible by these numbers: 1 2 59 and 118.
2 and 59
no it can be divided by two, most even numbers arnt prime
A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1 and 0. 1 and 0 are neither prime, nor composite. 118 is composite.
No. They both contain the factor 2. 68 = 2 x 2 x 17 118 = 2 x 59 Their LCM is 4012, not 68 x 118 = 8024
composite. prime #s can only be divided by 1 and itself
118 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 4 factors of 118 are 1, 2, 59, and 118.The factor pairs of 118 are 1 x 118 and 2 x 59.The proper factors of 118 are 1, 2, and 59 or,if the definition you are using excludes 1, they are 2 and 59.The prime factors of 118 are 2 and 59.The distinct prime factors of 118 are, since there is no repetition of prime factors, also 2 and 59.The prime factorization of 118 is 2 x 59.A factor = any number which can be divided into the given number with no remainder.1 and. 118
2 x 59 = 118
2 and 118.
The numbers that are divisible by 118 are infinite. Four of them are: 118, 236, 354, 472.Itself and any of its multiples
composite
As a product of its prime factors: 2 times 59 = 118
No.
No.