5
The prime factorization of 225 is (3^2 \times 5^2). To express this as a product of four prime numbers, we can write it as (3 \times 3 \times 5 \times 5). Thus, the four prime numbers that multiply to make 225 are 3, 3, 5, and 5.
The number 160 can be expressed as the product of its prime factors by first dividing it by the smallest prime numbers. The prime factorization of 160 is (2^5 \times 5^1). Thus, 160 can be written as (2 \times 2 \times 2 \times 2 \times 2 \times 5).
The prime factorization of 735 is (3 \times 5 \times 7 \times 7). However, since 7 is repeated, it does not constitute four distinct prime numbers. The four prime numbers that multiply to give 735, including repetition, are 3, 5, and two instances of 7. Thus, the prime numbers are 3, 5, 7, and 7.
The prime factorization of 110 is (2 \times 5 \times 11). This means that 110 can be expressed as the product of the prime numbers 2, 5, and 11.
The prime factorization of 375 is (3 \times 5^3). To express 375 as a product of four prime numbers, we can use the primes 3, 5, 5, and 5. Therefore, the four prime numbers that multiply to make 375 are 3, 5, 5, and 5.
The prime factorization of 225 is (3^2 \times 5^2). To express this as a product of four prime numbers, we can write it as (3 \times 3 \times 5 \times 5). Thus, the four prime numbers that multiply to make 225 are 3, 3, 5, and 5.
No they are not. A prime number is a number only divisible by 1 and itself, such as 5. These numbers can all be divided by two amoungst others and no number in the two times table (except two itself) is a prime number.
5 times 7 times x times y = 35xy 5 and 7 are prime numbers.
The number 160 can be expressed as the product of its prime factors by first dividing it by the smallest prime numbers. The prime factorization of 160 is (2^5 \times 5^1). Thus, 160 can be written as (2 \times 2 \times 2 \times 2 \times 2 \times 5).
The prime factorization of 735 is (3 \times 5 \times 7 \times 7). However, since 7 is repeated, it does not constitute four distinct prime numbers. The four prime numbers that multiply to give 735, including repetition, are 3, 5, and two instances of 7. Thus, the prime numbers are 3, 5, 7, and 7.
The prime factorization of 110 is (2 \times 5 \times 11). This means that 110 can be expressed as the product of the prime numbers 2, 5, and 11.
The prime factorization of 375 is (3 \times 5^3). To express 375 as a product of four prime numbers, we can use the primes 3, 5, 5, and 5. Therefore, the four prime numbers that multiply to make 375 are 3, 5, 5, and 5.
The product of two prime numbers can never be another prime number, the numbers that you multiplied are factors of the product. (example, 9 times 5 is 45, 9 and 5 go into 45)
The prime factorization of 105 is (3 \times 5 \times 7). To express this as a product of four prime numbers, we can include 1 as a prime number (though technically, 1 is not prime), yielding the combination (1 \times 3 \times 5 \times 7 = 105). However, if strictly considering only primes, the prime factors are 3, 5, and 7, which multiply to give 105. Therefore, there are not four distinct prime numbers that multiply to make 105.
No because prime numbers have only two factors.
They are 3 times 5 = 15
5*5*5 = 125