Q: What is the probability of 1 6 4 on 3 rolls of a die?

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The probability of rolling a 2 is 1 in 6. The probability of rolling an even number is 3 in 6. The probability of doing both, on two rolls, is 3 in 36, or 1 in 12.

It is 0.0227

If you keep rolling the die, the probability is 1. If you require a 3 and a 4 in the first two rolls, the answer is (1/6)*(1/6) = 1/36

Total different outcomes = 6Successful outcomes = 3 (rolls of 4, 5, or 6)Probability of success = 3/6 = 1/2 = 50%

Total number of possible rolls with 2 dice = 36.Total number of rolls that are doubles = 6.Probability of rolling doubles= 6/36 = 1/6 = (16 and 2/3) percent .

Related questions

The probability of rolling a 2 is 1 in 6. The probability of rolling an even number is 3 in 6. The probability of doing both, on two rolls, is 3 in 36, or 1 in 12.

The answer depends on how often the die is rolled. As the number of rolls increases, the probability gets near enough to 1 as makes no difference. For a single roll, the answer is 1/3.

The probability is 0.2503

1/4 = 0.25 If the second die is 1 or 2, then there are 12 possible outcomes. To score 7: 5+2 or 6+1 ⇒ 2 rolls To score 8: 6+2 ⇒ 1 roll ⇒ to score 7 or 8: 2 + 1 = 3 rolls So there are 3 rolls to score the required sums out of 12 possible rolls, giving a probability of: 3/12 = 1/4 = 0.25

It is 0.0227

If you keep rolling the die, the probability is 1. If you require a 3 and a 4 in the first two rolls, the answer is (1/6)*(1/6) = 1/36

Total different outcomes = 6Successful outcomes = 3 (rolls of 4, 5, or 6)Probability of success = 3/6 = 1/2 = 50%

Total number of possible rolls with 2 dice = 36.Total number of rolls that are doubles = 6.Probability of rolling doubles= 6/36 = 1/6 = (16 and 2/3) percent .

The probability of 3 specific dice rolls is the probability that each one will happen multiplied together. For instance, the probability of rolling 2 then 6 then 4 is the probability of all of these multiplied together: The probability of rolling 2 is 1/6. The probability of rolling 6 is 1/6. The probability of rolling 4 is 1/6. Multiply these together and we get the total probability as 1/216

1 in 36.

The theoretical probability of rolling something other than a factor of 6 in one roll is 2/6 or 1/3. So, the probability of rolling something other than a factor of 6 in 100 rolls is (1/3)^100 = 1.94*10-48 And therefore.the probability of rolling a factor of 6 is 1 - Prob(not a factor) = 1 - 1.94*10-48 which is incredibly close to 1.

When a die is rolled once, the probability of a 4 showing up is 1/6. Apply the binomial probability for finding the probability of exactly three fours out of 12 throws of a die. n=12 (number of throws) p=1/6 (probability of a four in a single throw) x = 3 (number of times out of 12 , a four showing up) P(x=3) = 12C3 (1/6)^3 (5/6)^(12-3) = 12C3 (1/6)^3 (5/6)^9 = 0.197443