The probability of the first card being red is 16 in 32. The probability of the second card being red is 15 in 31. The third is 14 in 30. The fourth is 13 in 29. Multiply these probabilities together and you get 16 x 15 x 14 x 13 in 32 x 31 x 30 x 29, which is equal to 43680 in 863040 or about 0.0506.
1/26
There are 8 marbles that aren't black, out of a total of 12 marbles, so the probability is 8/12 or 2/3.
The probability depends on:whether the cards are drawn randomly,how many cards are drawn, andwhether the cards are replaced before drawing the next card.If only 2 cards are drawn randomly, and without replacement, the probability is 0.00075 approximately.
(3/7)*(2/7)=(6/49) You have a 6 out of 49 probability.
The probability is zero, because there are no red balls in the bag.
1/26
50%
50%
There are 8 marbles that aren't black, out of a total of 12 marbles, so the probability is 8/12 or 2/3.
The probability depends on:whether the cards are drawn randomly,how many cards are drawn, andwhether the cards are replaced before drawing the next card.If only 2 cards are drawn randomly, and without replacement, the probability is 0.00075 approximately.
It is 5/52 for a single card, drawn randomly.
About a 3.8% chance (2 / 52 = 0.038...).
i think it would b 1 out of 12
(3/7)*(2/7)=(6/49) You have a 6 out of 49 probability.
The probability is zero, because there are no red balls in the bag.
In a monohybrid cross with black as dominant (B) and white as recessive (b), the probability of an offspring being black is 75% (3/4) and the probability of being white is 25% (1/4) according to the Punnett square ratios.
The theoretical probability of randomly picking each color marble is the number of color marbles you have for each color, divided by the total number of marbles. For example, the probability of selecting a red marble is 3/20.