for each ticket, it is the same as a regular raffle: one in 200
What is the probability of rolling an even with one roll of a numbers cube.
To calculate the odds of winning lotto where choose say 6 numbers out of 40 for example the calculation is 40X39X38X37X36X35 divided by 6X5X4X3X2X1 or about 3.8 million to 1 on any one line. If you have 45 numbers to choose from it would be 45X44X43X42X41X40/6X......etc or about 8.2 million to 1.
About 63.3968% Right. Winning AT LEAST once out of 100 tries is equal to NOT(NEVER winning in one of 100 tries). The one in the brackets is 0.99 ^100, which is about 0.33. Taking the NOT is subtracting that result from one, yielding about 0.63396766. To get a percentage multiply this by 100.
There are 6 possible numbers that can be rolled. "4" is one of those possible numbers. Probability is therefore 1/6.
An event which has a probablility of 1 is one that will definitely happen. Probabilities range between 0 and 1 (0% and 100%) with a probability of zero meaning it is impossible and a probability of one meaning that it is definite. i.e. winning the lottery if you never play has a probability of zero and winning the lottery if you know the correct numbers in advance has a probability of one.
for each ticket, it is the same as a regular raffle: one in 200
What is the probability of rolling an even with one roll of a numbers cube.
Winning the maximum jackpot in a lottery draw.
To calculate the odds of winning lotto where choose say 6 numbers out of 40 for example the calculation is 40X39X38X37X36X35 divided by 6X5X4X3X2X1 or about 3.8 million to 1 on any one line. If you have 45 numbers to choose from it would be 45X44X43X42X41X40/6X......etc or about 8.2 million to 1.
The odds are 1 in 200. The probability of winning is 0.005.
10,000,000 to one.
given that there are 6000 available tickets and 1 winner: If one buys 1 ticket he has a probability of 1/6000 of winning if one buys 14 tickets he has a probability of 14/6000 of winning if one buys 28 tickets he has a probability of 28/6000 of winning
About 63.3968% Right. Winning AT LEAST once out of 100 tries is equal to NOT(NEVER winning in one of 100 tries). The one in the brackets is 0.99 ^100, which is about 0.33. Taking the NOT is subtracting that result from one, yielding about 0.63396766. To get a percentage multiply this by 100.
The prime numbers from one to nine are 2, 3, 5, and 7. There are nine numbers from one to nine. The probability is 4 (the number of prime numbers) over 9 (the total number of numbers). Therefore, the probability of choosing a prime number is 4/9 or about 44 percent.
There are 6 possible numbers that can be rolled. "4" is one of those possible numbers. Probability is therefore 1/6.
A fair chance of winning is more than 50% chance of winning. Therefore probability = 0.5 We need to find a fair chance of winning atleast one match. 1-(5/6)^n > 0.5 hence, n=4 QED (quite easily done, :-p)