The prime numbers from one to nine are 2, 3, 5, and 7. There are nine numbers from one to nine. The probability is 4 (the number of prime numbers) over 9 (the total number of numbers). Therefore, the probability of choosing a Prime number is 4/9 or about 44 percent.
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The prime numbers from 1-6 are 2, 3, 5 (1 is not prime). There are 3 prime numbers on a dice and 6 total. therefore the probability of rolling a prime is 3/6. The probability of getting a tails when flipping a coin is 1/2. Therefore you just multiply the two. 3/6 * 1/2 = 1/4
Prime numbers from 1 to 15 are: 2 3 5 7 11 and 13 So the probability is: 6/15 or as 2/5
On a standard die, 2:1 in favour. This would be correct if 1 and 2 are accepted as prime numbers, which is allowed by some mathematicians and theories though not by all. ---- Having worked it out myself, I believe there is actually an even probability: Prime numbers: * 2 * 3 * 5 Not-prime numbers: * 1 * 4 * 6
The three prime numbers on the cube are: 2 3 and 5 so the probability is 3/6 or 1/2 simplified
"The probability of getting a prime number in a die is 4/6" Actually there are 3 prime numbers on a die. 2, 3, and 5 are all prime numbers. So this tells you that you have 3 chances it will be a prime number and 3 chances it will not be a prime number. So the probability of getting a prime number on a die would be 3/6 or 1/2.