There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.
However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of 13 boys in a family with 13 children is approx 0.00019.
1/32
The odds of a four-child family having four boys can be calculated using the probability of each child being a boy, which is typically 1/2. Therefore, the probability of having four boys in a row is (1/2) × (1/2) × (1/2) × (1/2) = 1/16. This means the odds against having four boys are 15 to 1, as there are 15 other combinations of boys and girls possible in four children.
The probability of having 2 boys and 1 girl in a family with three children can be calculated using the binomial probability formula. Assuming the probability of having a boy or a girl is equal (1/2 each), the probability of having 2 boys and 1 girl can be found by considering the different combinations (BBG, BGB, GBB). Therefore, the probability is ( \frac{3}{8} ) or 37.5%.
It depends on the context: if you select a child at random from a girls' school, the probability is 0, while if it is at a boys' school it is 1!
50/50
1/4
1/32
In a family with four children, the probability of having four boys is 1 in 16.
50/50
50%....maybe you're not cut out for college....
50%
There is no simple answer.First of all, the probability of boys is 0.517 not0.5.Second, the probabilities are not independent.If you choose to ignore these important facts, then the answer is 2/3.
The probability of an individual having either a male or female can not be altered. There is always a 50/50 chance of having a boy or girl. It is not a genetic trait to have one of the other.
25
It depends on the context: if you select a child at random from a girls' school, the probability is 0, while if it is at a boys' school it is 1!
1/8
50/50