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What is the probability of a girl being chosen if there are 10 boys and 14 girls?
If the choice is unbiased, the change is 14/(10+14). If the chooser prefers choosing boys, the probability is 0.
If a coin is tossed for 30 times what is the probability of having 10 heads?
10 :)
There are 15 girls and 10 boys in a math class what is the probability of not choosing a girl?
2/5
A hat contained 10 boys and 20 girl names What is the chance of picking out a boy's name?
The probability of picking out a boy's name from the hat can be calculated by dividing the number of boy names by the total number of names in the hat. In this case, there are 10 boy names and 30 total names (10 boys + 20 girls). Therefore, the probability of picking out a boy's name is 10/30 or 1/3, which can also be expressed as approximately 0.333 or 33.33%.
If a coin is tossed for 30 times what is the probability of having no heads?
No heads means that every toss lands tails. (0.5)30= 9.3 x 10-10 Note that 109 = 1 trillion, so the probability can be stated this event is likely to occur about 9 times in 10 trillion tosses.
What is the probability of having exactly 8 boys in 10 births?
For each birth, you have two choices - either a boy or a girl. Then, the probability for a certain birth to obtain a choice is ½. Using Binomial Theorem, we have (10 choose 8)(½)8(½)² = 45/1024.
What is the probability of exactly 7 boys in 10 births when the birth of any child does not affect the probability of the gender of any other children?
This is a Binomial Probability; p=0.5, n=10 & x=7. Since you want the probability of exactly 7, in the related link calculator, after placing in the above values, P(x=7) = 0.1172 or 11.72%.
What is the probability of a girl being chosen if there are 10 boys and 14 girls?
If the choice is unbiased, the change is 14/(10+14). If the chooser prefers choosing boys, the probability is 0.
If a coin is tossed for 30 times what is the probability of having 10 heads?
10 :)
What is the probability of getting a license plate that has a repeated letter or digit if you live in a state that has three numerals followed by two letters followed by three numerals?
This is one minus the probability of having no repeated letters. The probability of having no repeated numbers is 10/10 x 9/10 x 8/10 x 7/10 x 6/10 x 5/10 which equals 0.1512. The probability of having no repeated letters is 26/26 x 25/26 = 0.96153846153846153846153846153846 These multiplied together gives 0.14538461538461538461538461538462 1 minus this is 0.85461538461538461538461538461538 And so the probability of having a repeater letter or digit is roughly 0.855
There are 15 girls and 10 boys in a math class what is the probability of not choosing a girl?
2/5
What is the probability you will select a girl from the class if you have 17 girls and 10 boys?
Oh, dude, let me break it down for you. So, if you have 17 girls and 10 boys in the class, the probability of selecting a girl is like the number of girls divided by the total number of students. So, it's 17 girls out of 27 students, which simplifies to about 63%. Cool, right?
If 8 women are pregnant what is the probability that there will be 4 boys and what is the probability that at least 7 girls will be born?
Assuming that the probability of 1 woman have a boy is .5 Binomial Distribution can be used to solve the problem. b(k;n,p) = (n choose k) p^k * (1-p)^(n-k) k= number of boys n= number of trials p= probability of boy Assume p is equal to probability of having a boy First question we are looking for four boys. ie k=4 n = 10 =(10 choose 4) 0.5^4 * (1-.5)^4 = 0.8203 Question 2) At least 7 girls means 1 boy or 0 boys will be born Case 1) 0 boys born Use binomial (10 choose 0) 0.5^0 * (1-.5)^8 = 0.00390625 Case 2) 1 boy born (10 choose 1) 0.5^1 * (0.5)^7 =0.0390625 Case 1 + Case 2= 0.04296875 Probability of at least 7 girls
What is probability 2 girls are chosen if 10 students are girls and 15 are boys?
The probability of choosing 2 girls at random from group of 25 students of which10 are girls and 15 are boys is:P( 2 girls) = (10/25)∙(9/24) = 3/20 = 0.15 = 15%
What is the probability of having 4 consecutive successes in 10 trials?
More information is needed to determine the answer to the question. We need to know the probability of success or failure.
Luna is expecting her child What is probability of having a girl after 10 female children?
1/2
A class of 25 students has 15 girls and 10 boys If one student is chosen at random What is the probability it is a girl?
The probability is 15/25 = 3/5
