80%
Each outcome has a probability of 0.05
20% = 1 out of 5 = 1/5 = a fifth 50% = 1 out of 2 = 1/2 = a halve
0 to 20%
The random variable has a Poisson distribution with parameter L = 1*50/20 = 2.5. So Prob(at least one event in 50 years) = 1 - Prob(No events) = 1 - L0e-L/0! = 1 - e-2.5 = 0.918 approx.
Using the Poisson approximation, the probability is 0.0418
The probability of at least one event occurring out of several events is equal to one minus the probability of none of the events occurring. This is a binomial probability problem. Go to any binomial probability table with p=0.2, n=3 and the probability of 0 is 0.512. Therefore, 1-0.512 is 0.488 which is the probability of at least 1 sale.
IF probability of rain is X percent then probability of no rain is 100- X percent. For example if prob of rain is 80% prob of no rain is 20%
It means that there is a probability or chance of 0.05 or 1 in 20 of observing the relevant event.
7/20 = NN = 0.35 = 35 percent
Each outcome has a probability of 0.05
20% = 1 out of 5 = 1/5 = a fifth 50% = 1 out of 2 = 1/2 = a halve
0 to 20%
The random variable has a Poisson distribution with parameter L = 1*50/20 = 2.5. So Prob(at least one event in 50 years) = 1 - Prob(No events) = 1 - L0e-L/0! = 1 - e-2.5 = 0.918 approx.
Using the Poisson approximation, the probability is 0.0418
Theoretical probability = 0.5 Experimental probability = 20% more = 0.6 In 50 tosses, that would imply 30 heads.
Probability of pass on second attempt is 40% x 80% = 32%
Yes. The probability of this occurring is 0.520 = 0.00000095367 or 1 in 1,048,576 thus you are more likely to do this than win the lottery