February 29 occurs 97 times in 400 years (not once in 4 years). Therefore, there are 97 favourable events out of 146,097 days which gives a probability of 0.00066 approx.
However, this assumes that birthdays are randomly spread over the course of a year. This is certainly not true, and February is "low season" for births so the true probability will be lower.
The probability is 29/36.
The probability of the first card being red is 16 in 32. The probability of the second card being red is 15 in 31. The third is 14 in 30. The fourth is 13 in 29. Multiply these probabilities together and you get 16 x 15 x 14 x 13 in 32 x 31 x 30 x 29, which is equal to 43680 in 863040 or about 0.0506.
Birthdays are not uniformly distributed over the year. Also, if you were born on 29 February, for example, the probability would be much smaller. Ignoring these two factors, the probability is 0.0082
11 months have 29 days..........Only feb has 29 days in the leap year otherwise it has 28 days.
To select the first birthday, the probability is 1/30. Having gotten that, the conditional probability that the next birthday would be the same is (1/30)x(1/29) and that is 1/870----------------------------------------------------------------------------------------------I believe the question has to be rephrased to "What is the probability that two peoplein a group of 30 people share the same birthday?". Because in the way the questionis actually stated, "the probability that two persons selected randomly from a group of 30 have the same birthday", the event that "those two people would share theirbirthday" is independent of the size of the population they were selected from.In the case the actual question be "What is the probability that two people in a groupof 30 share the same birthday?, is given by the following expression that neglectsFebruary 29 (of the leap), but gives very good approximation to the expression thatconsiders February 29 and is a simpler one. [It has to be mentioned that the analysisleading to this expression considers birthdays a "random variable" where chances fora persons birthday are the same for any day of the year]:P(2 share bd out of n) = nC2 (1/365) Π1n-1[1-(i-1)/365]for n = 30, P(2 share bd out of 30) = 30C2 (1/365) Π1 29 [1-(i-1)/365] = 435∙(1/365)∙[1-1/365]∙[1-2/365]∙[1-3/365]∙ ∙∙∙ ∙[1-28/365] = 0.380215577... ≈ 0.380 ≈ 38.0%For the construction of the expression to calculate the probability of any two people sharing a birthday in a group of n people considering Feb 29 of the leap year see thequestion "What is the probability that in a room of 8 people 2 have the same birthday?"
The odds of a baby being born on February 29, a leap day, are approximately 1 in 1,461, as it only occurs once every four years.
1,556,232,100 people are born on a leap year!
Well I'm born on Feb 29 , and i celebrate it on March 1st !! ;) But its kinda annoying and special (at the same time) to be born on Feb 29 !! :P
11 years old born feb.29 2000
born Feb. 11, 1979 therefore age 29
she must have been born on 29 feb 1960.. simple
he is 29 to this date, he was born feb 17 1980
feb 29
It was a Wednesday.
Monday
29-Feb
feb 29