If you draw enough balls, without replacement, the probability is 1.
The answer depends on
Unfortunately, your question gives no information on these matters.
(3/7)*(2/7)=(6/49) You have a 6 out of 49 probability.
The probability is 0.
The probability is zero, because there are no red balls in the bag.
The probability of choosing a red or black card from a standard deck of 52 cards is 52 in 52, or 1 in 1. In other words, it will happen no matter what.
It is 2/52 or 1/26.
(3/7)*(2/7)=(6/49) You have a 6 out of 49 probability.
2
11/18 x 10/17 = .359
A laundry bag contains 160 black socks and 300 red socks. 1940 black socks must be added so that the probability of choosing a black sock is 7 of 8.
The probability of a black ball in bag 1 is 4/12 = 1/3. If you add 3 black balls to bag 2, it will contain 5 black balls out of 15: the probability of a black ball being 3/15 = 1/3.
The probability is 0.
The probability, or probility, even, is 0 since tere can be no such thing as "choosing red card of the black".
The probability is zero, because there are no red balls in the bag.
The probability of choosing a red or black card from a standard deck of 52 cards is 52 in 52, or 1 in 1. In other words, it will happen no matter what.
The probability is: 55/200 or 11/40
3/12*3/11 = 9/132, or 6.818%.
It is 2/52 or 1/26.