If you draw enough balls, without replacement, the probability is 1.
The answer depends on
Unfortunately, your question gives no information on these matters.
(3/7)*(2/7)=(6/49) You have a 6 out of 49 probability.
The probability is 0.
The probability is zero, because there are no red balls in the bag.
The probability of choosing a red or black card from a standard deck of 52 cards is 52 in 52, or 1 in 1. In other words, it will happen no matter what.
3/12*3/11 = 9/132, or 6.818%.
(3/7)*(2/7)=(6/49) You have a 6 out of 49 probability.
2
11/18 x 10/17 = .359
A laundry bag contains 160 black socks and 300 red socks. 1940 black socks must be added so that the probability of choosing a black sock is 7 of 8.
The probability of a black ball in bag 1 is 4/12 = 1/3. If you add 3 black balls to bag 2, it will contain 5 black balls out of 15: the probability of a black ball being 3/15 = 1/3.
The probability is 0.
The probability, or probility, even, is 0 since tere can be no such thing as "choosing red card of the black".
The probability is zero, because there are no red balls in the bag.
The probability is: 55/200 or 11/40
The probability of choosing a red or black card from a standard deck of 52 cards is 52 in 52, or 1 in 1. In other words, it will happen no matter what.
3/12*3/11 = 9/132, or 6.818%.
It is 2/52 or 1/26.