7/26
The answer depends on whether or not the first card is replaced before the second is drawn.
It is 13/51.
The probability of drawing a jack, queen, or king on the second draw if the first draw was an ace (without replacement) is (4 + 4 + 4) in (52 - 1) or 12 in 51, which is 4 in 17, or about 0.2353.
The probability is 0.
16 out of 52
If 1 queen was drawn out of the 52 card deck without replacement, the probability of choosing a queen on the 2nd draw is 3/51 or 1/17.
Two cards are drawn from a pack of 52 cards second card is drawn after replacing the first card. What is the probability that the second card is a king?
The answer depends on whether or not the first card is replaced before the second is drawn.
It is 13/51.
The probability of drawing a jack, queen, or king on the second draw if the first draw was an ace (without replacement) is (4 + 4 + 4) in (52 - 1) or 12 in 51, which is 4 in 17, or about 0.2353.
They are independent, because the probability of the first event does not affect the probability of the second event.
The probability is 0.
It is 13/52 = 1/4.
16 out of 52
The probability, or probility, even, is 0 since tere can be no such thing as "choosing red card of the black".
It is 156/663 = 0.2353, approx.
The probability that the first card is a jack is 4 in 52. The probability that the second card is 1 ten is 4 in 51. Since these are sequential events, simply multiply, giving (4/52)(4/51) or (16/2652) or about 0.00603.