The probability is 2/11.
The sample space is {m, a, t, h, e, i, c, s} which, curiously, is also the sample space for choosing a letter from my user name!
The sample space is {p, r, o, b, a, i, l, t, e, s}
3 in 8, 0.375, if you consider the y as a consonant, 4 in 8, 0.5, if not.
4 because in word perseverance we have 4 letters E
Probability of choosing a consonant from math = 3/4
Since the word "probability" contains only letters, then the probability of choosing a letter from the word "probability" is 1, i.e. it is certain to happen.
The sample space consists of the letters of the word "PROBABILITY" = {P,R,O,B,A,I,L,T,Y}
2/11
The probability is 2/11.
1/6 if the letter is chosen at random.
There are 11 letters in the word mathematics. 2 of those 11 are A's. Probability is therefore 2/11.
The sample space is {m, a, t, h, e, i, c, s} which, curiously, is also the sample space for choosing a letter from my user name!
The odds are 2/11 (two out of eleven), or 18.18%.
The sample space for choosing a letter from the word SPACE is {S, P, A, C, E}. The sample space for choosing a consonant from the word MATH is {M, T, H}. Consonants are letters that are not vowels (A, E, I, O, U), so in the word MATH, the consonants are M, T, and H.
The sample space is {p, r, o, b, a, i, l, t, e, s}
11 * * * * * No, on two counts. The sample space is the possible outcomes of the experiment, not the NUMBER of possible outcomes. And, as far as this experiment is concerned, there is no way to distinguish between the two occurrences of b and i. So there are, in fact, only 9 possible outcomes. Two of these outcomes have a higher probability but that is a different matter. The sample space is {p, r , o , b, a, i, l, t, y} a set of cardinality 9.