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1/6 if the letter is chosen at random.

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Q: What is the probability of choosing S in the word SCHOOL?
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What is the probability of picking an s in the word Mississippi?

The probability of picking an 's' in the word Mississippi is 100% - you will always find one ... eventually. However if you mean with single choice from the 11 characters of the word Mississippi, then the probability is 4 chances in 11 which is just over 36% or a probability of 0.363636 recurring. My odd answer illustrates the need to pose questions without ambiguity. Beano GB


What is the probability of drawing a vowel from the word mathematics?

You have a total of 11 letters in "mathematics" and you have 4 vowels (a,e,a,i) so the probability of drawing a vowel is 4/11. In other words if you were to consider the vowel's to be 1's and the consonants 2's. What is the probability of drawing a "1". There would be 4 1's and 7 2's. It would be 4/11


Find the sample space for choosing a letter from the word SPACE and choosing a consonant from the word MATH.?

The sample space for choosing a letter from the word SPACE is {S, P, A, C, E}. The sample space for choosing a consonant from the word MATH is {M, T, H}. Consonants are letters that are not vowels (A, E, I, O, U), so in the word MATH, the consonants are M, T, and H.


What is the probability of selcting two s's if the first card is not replaced before selcting the second card?

There are no s's in a standard deck of cards, so the probability of selecting any s's, in any sequence of draws, in any strategy of replacement is exactly zero.


What is classical probability?

Classical probability theory is concerned with carrying out probability calculations based on equally likely outcomes. That is, it is assumed that the sample space has been constructed in such a way that every subset of the sample space consisting of a single element has the same probability. If the sample space contains n possible outcomes (#S = n), we must have for all s 2 S, P(fsg) = 1 n and hence for all E S P(E) = #E n : More informally, we have P(E) = number of ways E can occur total number of outcomes :

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