There are 13 of each suit in a standard deck of cards. Assuming there are no jokers, the probability of picking either a club or a diamond is (13+13)/52 or 0.5. There are also four aces in a standard deck. However, we've already accounted for two of them (the ace of clubs and the ace of diamonds), so we're only adding two additional possibilities. The probability of choosing an ace, a club, or a diamond from a standard deck is therefore 28/52 (you can figure the decimal value yourself).
1/2 or .50. Of the 52 cards, 26 are either a heart or a diamond (there are 13 hearts, 13 diamonds, 13 clubs and 13 spades).
If you mean chosing both cards - the odds are 1 in 169. If you mean chosing either a king or a queen - the odds are 1 in 13
The probability is 11/13.
On one random draw, the probability is 2/13.
This is the same as the probability of choosing either a red of a blue marble. There are 5+4 out of 15 ways of doing this. The probability is therefore 9/15 = 3/5.
either 4 in 52 chances or 1 in 13 chances.
There are 13 of each suit in a standard deck of cards. Assuming there are no jokers, the probability of picking either a club or a diamond is (13+13)/52 or 0.5. There are also four aces in a standard deck. However, we've already accounted for two of them (the ace of clubs and the ace of diamonds), so we're only adding two additional possibilities. The probability of choosing an ace, a club, or a diamond from a standard deck is therefore 28/52 (you can figure the decimal value yourself).
26/52 cards are black and 13/52 cards are diamonds so the total probability of either a diamond or a black card is 39/52 or 3/4 p = 0.75
1/2 or .50. Of the 52 cards, 26 are either a heart or a diamond (there are 13 hearts, 13 diamonds, 13 clubs and 13 spades).
If you mean chosing both cards - the odds are 1 in 169. If you mean chosing either a king or a queen - the odds are 1 in 13
Assume that you start with a well-shuffled regular 52-card deck (no jokers) and draw 2 cards. The first card can be either a spade or a diamond, giving you 26 possibilities out of the 52 cards, for a probability of 26/52 or 1/2. The second card must be of the other desired suit, giving you 13 possibilities out of the 51 remaining cards, for a probability of 13/51. The total probability is then the product of the two, 1/2 x 13/51 = 13/102, or about 12.74%.
Since it is a certainty that a coin must land on either heads or tails, the probability must be 1.
The probability is 11/13.
i dont know it either...hahaha^^
Probability concerns with estimating a likelyhood for an event to either yet to happen or would have happened.
On one random draw, the probability is 2/13.