Hey,
to start,, i am not a math guy at all, i have a couple years of philosophy and psych but nothing to be proud of,, just a drunk (little too much drugs) guy whose bored on the internet and now really wants someone to finish what ive got so far.
So theres 3 possible outcomes when dealing the cards. "theres more than 3 looking at the suites, but only 3 as far as the probabilities go, take a second look if u dont know what i mean,,haha also if you dont u cant help me :( "
A A S S S
26/52* 25/51* 13/50* 12/49* 11/48 = .0035
A S A S S
26/52* 25/51* 24/50* 12/49* 11/48 = .0066
S S A A S
26/52* 25/51* 24/50* 23/49* 11/48 =.0127
1/4 of spade
1/4 of Ace
now you would look at scenario 3 and say that the prob of getting s,s,a is already--like another popular wikianswer shows,,
prob of #3 (ssa)
(1/4) (4/17) (13/50), =0.0153
and would already been thrown off..
but...u have to remember we have no specific order, which makes this question so difficult (for me at least)
the probability of the 3rd and 4th card being either a spade or heart is where its tough for me,
also that im doing this using my stickies and calculator on my macbook at 3am drunk would make it hard, was just interested in this question because i really enjoy Poker.
,,so that leaves us at the question,, how do we take the prob of the 3rd and 4th card being either heart or spade (ignoring the reacquiring probabilities, and understanding theres only 3 outcomes) and make a new probability. Even if i were to find those probs how do i inculde them into the 3 other probs i have on the scenarios.
Ill check this again, but if your wicked with your numbers could you please also email the solution to me ryen_00 at hotmail.com
...sorry to the question asker that i have no number for ya,,, i prob could have bullshitted an answer but i wanna know the real one now.
-----------------------------------------------------------------------------------------------------
WOKE UP SOBER,, I THINK ITS JUST AS EASY AS ADDING THE 3 POSSIBLE CASES TOGETHER
.0035+.0066+.0127= .0228
OR approx: 1/44
There are 52 cards in a deck and 1 ace of spades. So the probability is 1/52 or unlikely.
The probability is 4/52*3/51 ~= 0.0045 = 0.45%
A pinochle deck consists of 48 cards. Eight of these cards are aces (2 aces per suit * 4 suits = 8 aces). So, for a random drawing from a complete pinochle deck, the probability of drawing an ace is 8/48 = 1/6.
The probability of drawing three aces from a deck of cards is 1 in 5525. The probability of the first ace is 4 in 52, or 1 in 13. The second ace is 3 in 51, or 1 in 17. The third ace is 2 in 50, or 1 in 25. Multiply these three probabilities together and you get 1 in 5525.
Of 26 black cards, 2 are aces... 1 in 13, or ~7.7%.
There are 52 cards in a deck and 1 ace of spades. So the probability is 1/52 or unlikely.
The probability is 4/52*3/51 ~= 0.0045 = 0.45%
There are 52 cards in a deck there are 4 aces and 4 kings which makes a total of 8 kings and aces. Assuming that the deck is full and shuffled the probability of drawing an aces or a king is 8/52 which simplifies to 2/13
A pinochle deck consists of 48 cards. Eight of these cards are aces (2 aces per suit * 4 suits = 8 aces). So, for a random drawing from a complete pinochle deck, the probability of drawing an ace is 8/48 = 1/6.
The probability of drawing the first ace is 4 in 52. The probability of getting the second ace is 3 in 51. The probability of getting the third ace is 2 in 50. The probability, then, of drawing three aces is (4 in 52) times (3 in 51) times (2 in 50), which is 24 in 132600, or 1 in 5525, or about 0.0001810
The probability of drawing three aces from a deck of cards is 1 in 5525. The probability of the first ace is 4 in 52, or 1 in 13. The second ace is 3 in 51, or 1 in 17. The third ace is 2 in 50, or 1 in 25. Multiply these three probabilities together and you get 1 in 5525.
4/52 X 3/51 x 2/50.
Of 26 black cards, 2 are aces... 1 in 13, or ~7.7%.
Reason:There are only 2 cards in the deck of 52 which could be either a Queen of Clubs or Queen or Spades, So there is a 2 out of 52 chance, or 3.8461538 % chance.
If you just draw two cards, 1/13 times 1/12 i.e. 1/156
Not necessarily. The probability of a complementary event with probability p is 1-p. Two mutually exclusive events, however, don't necessarily add up to a probability of 1. For example, the probability of drawing a King from a standard deck of cards is 1 in 13, which the complementary probability of not drawing a King is 12 in 13. The probability, however, of drawing a Heart is 1 in 4, while the probability of drawing a Club is also 1 in 4. That leaves Diamonds and Spades, which account for the remaining probability of 2 in 4.
The probability of drawing a king given that you drew a spade or a club is 2 out of 26, or 1 out of 13. This is because there are 2 kings (one from spades and one from clubs) out of a total of 26 spade and club cards.