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What is the probability of drawing a king and a jack in two successive draws from a deck of cards with replacement?
It is 1/169 = 0.005917, approx.
What is the probability of an ace and a king in two blind draws without replacement?
Abolut 4 in208
What does replacement mean in probability?
When the sample is drawn, it is placed back where it was taken from and if subsequent draws are made, it could be selected again.
What is the probability that one is a club and one is a diamond?
To determine the probability that one card drawn is a club and the other is a diamond from a standard deck of 52 cards, you can use the concept of combinations. There are 13 clubs and 13 diamonds in the deck. The probability of drawing one club and one diamond in two draws (without replacement) can be calculated as follows: the probability of drawing a club first and then a diamond is (13/52) * (13/51), and the probability of drawing a diamond first and then a club is (13/52) * (13/51). Adding these two probabilities gives you the total probability of one card being a club and the other a diamond. The final probability is approximately 0.25 or 25%.
What is the probability of drawing a red card and a spade in two draws without replacing?
The probability of drawing a red card followed by a spade is (1 in 2) times (1 in 4), or 1 in 8, or 0.125. The probability of drawing a spade followed by a red card is (1 in 4) times (1 in 2), or 1 in 8, or 0.125. Since you have two distinct desired outcomes, add them together, giving a probability of drawing a red card and a spade of 0.25.
What is the probability of drawing three aces in a row without replacement?
The probability of drawing aces on the first three draws is approx 0.0001810
What is the probability of drawing a king and a jack in two successive draws from a deck of cards with replacement?
It is 1/169 = 0.005917, approx.
What is the probability of drawing an ace then a diamond on two draws with replacement?
4/52 x 13/52 = 1/13 x 1/4 = 1/52
If a box contains three blue cards and three white cards If two cards are drawn one at a time find the probability that both cards are blue if the draws are made with replacement?
The probability of drawing two blue cards froma box with 3 blue cards and 3 white cards, with replacement, is 1 in 4, or 0.25.The probability of drawing one blue card is 0.5, so the probability of drawing two is 0.5 squared, or 0.25.
What is the probability of drawing at least one spade in two draws without replacing?
It is approx 0.44
What is the probability of an ace and a king in two blind draws without replacement?
Abolut 4 in208
What is the probability of drawing of exactly one 9 if you draw two cards without replacement from a deck of cards?
Let's call the chance of drawing a 9 on the first draw P(A). Since there are four 9s, P(A) is 4/52. Probability of not drawing a 9 is 1-(4/52). Each draw is independent so we multiply the probabilities. The probability of EXACTLY one 9 in two draws if P(A)P(1-A)=12/169 which is a about .071
What is the probability of drawing an ace and a face card from a deck of cards on the first two draws from the deck?
4/221
What is an event that occurs because of a preceding event?
A dependent event. Or rather, a dependent event is one whose probability of occurrence is affected by previous events. For instance, drawing a card from a deck is affected by previous draws, if there's no replacement.
What is the probability of drawing two diamonds in two draws without replacing?
The probability of drawing a diamond from a standard 52-card poker deck without jokers is 13/52, or 1/4. The probability of drawing a second diamond at that point would then be 12/51, for an overall probability of 12/212, or 3/53. This amounts to about a 5.88% chance.
What does replacement mean in probability?
When the sample is drawn, it is placed back where it was taken from and if subsequent draws are made, it could be selected again.
What is the probability that one is a club and one is a diamond?
To determine the probability that one card drawn is a club and the other is a diamond from a standard deck of 52 cards, you can use the concept of combinations. There are 13 clubs and 13 diamonds in the deck. The probability of drawing one club and one diamond in two draws (without replacement) can be calculated as follows: the probability of drawing a club first and then a diamond is (13/52) * (13/51), and the probability of drawing a diamond first and then a club is (13/52) * (13/51). Adding these two probabilities gives you the total probability of one card being a club and the other a diamond. The final probability is approximately 0.25 or 25%.
