None, since that would imply that in 18 cases the coin did not show heads or tails!
The probability of getting all tails is 1/25 = 1/32
HHHHHTHTHTHHHTTTHTTTHTTTOf the 8 possibilities, 3 have 2 heads and 1 tails. So the probability is 3/8 (assuming a fair coin)
The probability of flipping one coin and getting tails is 1/2. In order to find the probability of multiple events occurring, you find the product of all the events. For 3 coins the probability of getting tails 3 times is 1/8 because .5 x .5 x .5 = .125 or 1/8.
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1 in two but they say the side with heads is slightly Heavier.
The probabilty of you flipping 3 coins and getting all heads or tails is 0.125 or 1/8.
The probability of getting all heads is 1/24 = 1/16 The probability of getting all tails is also 1/24 = 1/16 The probability of all heads or all tails is the sum of the two = 1/8
http://wiki.answers.com/Q/If_you_Flip_four_coins_at_once_what_is_probability_of_2_head_and_3_tail" The probability of flipping four coins and getting 2 heads and 3 tails is ZERO 2 heads and 3 tails requires flipping FIVE coins.
The probability of getting all tails is 1/25 = 1/32
Neither. Its a 50:50 probability. In the long run, heads will match tails.
Theoretical is 50% Heads, 50% tails: 30-Heads, 30-Tails (theoretical)
HHHHHTHTHTHHHTTTHTTTHTTTOf the 8 possibilities, 3 have 2 heads and 1 tails. So the probability is 3/8 (assuming a fair coin)
If they are fair coins, the probability is 0.25
The probability of flipping one coin and getting tails is 1/2. In order to find the probability of multiple events occurring, you find the product of all the events. For 3 coins the probability of getting tails 3 times is 1/8 because .5 x .5 x .5 = .125 or 1/8.
It is 1/2.
Every time you flip a coin it has a 50% chance of heads and a 50% chance of tails. Flipping a coin multiple times does not change that. Therefore the answer is 50%
If you mean what is the probability of getting a heads/tails, it is a 1 in 2 chance (50/50 chance). You are just as likely to get a heads as you are to get a tails.