2/16 = 1/8 or 12.5
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The probability of NOT getting heads is (1/2)4=1/16 Therefore the probability of getting heads is 1-1/16=15/16
Assuming a 6 sided die, a roll of 2 gives a maximum value of 12. So the probability of getting a 16 is zero.
If you look at the as the probability of getting 1 or more tail in 4 coin tosses, you would then calculate the probability of tossing 4 heads in a row and subracting that from 1. The probability fo tossing 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16. 1 - 1/16 = 15/16.
If 2 standard dice are rolled, the odds of getting a sum of 16 is zero. The highest sum possible is 12.
Oh, what a happy little question! Let's break it down. The probability of getting heads on a single flip is 1/2, and the probability of getting tails is also 1/2. So, the probability of getting HTTH in that specific order on four flips would be (1/2) * (1/2) * (1/2) * (1/2) = 1/16. Just remember, there are no mistakes, just happy little accidents in probability!