What is the probability of getting exactly two heads with 4 coin tosses?

Answer 1

To find the probability of getting exactly two heads in four coin tosses, we can use the binomial probability formula. The number of ways to choose 2 heads from 4 tosses is given by the binomial coefficient ( \binom{4}{2} = 6 ). The probability of getting heads on each toss is ( \frac{1}{2} ), so the probability of getting exactly 2 heads is ( \binom{4}{2} \times \left(\frac{1}{2}\right)^2 \times \left(\frac{1}{2}\right)^2 = 6 \times \frac{1}{16} = \frac{6}{16} = \frac{3}{8} ). Thus, the probability of getting exactly two heads is ( \frac{3}{8} ).