The answer depends on the design of the spinner: how many sides and what numbers on them.
If a five color spinner with equal sections of red blue green yellow and orange is spun six times, the probability of getting no reds in all six spins is 26.2%. The probability of no red on one spin is 4 out of 5, or 0.8 The probability of no red in six spins is 0.86.
The answer depends on the shape of the spinner and the numbers on it.
Well it would really depend on how many sections there are in the spinner and how many 3's and 5's there are.
If the probability of an event will occur is p, then the probability that it will occur in n trials is pn.(That's p raised to the n power). So if you bet on 12 numbers, then (38-12=26) numbers are empty. The probability of the ball landing on one of these empty numbers is 26/38. So (26/38)^11 = 0.01538, which is about 1.538 % or a 1 in 65 chance.
There is 1 section numbered 1, 5 sections numbered 2 and 2 sections numbered 3.
If a five color spinner with equal sections of red blue green yellow and orange is spun six times, the probability of getting no reds in all six spins is 26.2%. The probability of no red on one spin is 4 out of 5, or 0.8 The probability of no red in six spins is 0.86.
The probability that a spinner with N sides stops on 2 particular numbers in two spins in 1 in N2. It does not matter what the two numbers are, since the two spins are sequentially unrelated.
The answer depends on the shape of the spinner and the numbers on it.
Well it would really depend on how many sections there are in the spinner and how many 3's and 5's there are.
I'm assuming that a "1-8 spinner" is similar to an eight-sided die, so the probability of spinning a 10 is zero. When throwing dice, or flipping a coin, etc., each outcome is independent. That is, it's not influenced by the previous outcome(s). So if you get three 8s in a row then the probability of getting an 8 on the fourth throw remains at 1/8. The probability of an 8 on each and every throw is always 1/8.
The probability of landing on black twice on a spinner with white, black, and striped sections is (1/3)^2 = 1/9. This is because there is a 1/3 chance of landing on black on each spin, and the spins are independent events.
because it spins when it jumps out of the water
The spinner dolphin.
A Dusra is when an off spinner bowls a ball that looks like it will off-spin, but spins away to the left, like a leg spinner. When a leg-spinner does this it is a googly
Well, if the spinner has equal sections, and green is one of them, then statistically speaking, you would expect it to land on green about 100 times out of 600 spins. But hey, life's full of surprises, so don't bet your retirement savings on it!
Independent.
A spinner or spin tile