The conditional probability is 1/4.
1/2
Pr(At least one head in three tosses) = 1 - Pr(No heads in three tosses) = 1 - Pr(Three tails in three tosses) = 1 - (1/2)*(1/2)*(1/2) = 1 - 1/8 = 7/8 or 0.875 or 87.5%
It is (1/2)3 = 1/8
Assuming it is a fair coin, the probability is 1/24 = 1/16.
The conditional probability is 1/4.
0.1222...
The probability of tossing two heads in two coins is 0.25.
0.5
1/2
By tossing two coins the possible outcomes are:H & HH & TT & HT & TThus the probability of getting exactly 1 head is 2 out 4 or 50%. If the question was what is the probability of getting at least 1 head then the probability is 3 out of 4 or 75%
The probability would be once in 128 attempts. You don't have to toss seven coins simultaneously. the 7 tosses just have to be independent of one another.
Pr(At least one head in three tosses) = 1 - Pr(No heads in three tosses) = 1 - Pr(Three tails in three tosses) = 1 - (1/2)*(1/2)*(1/2) = 1 - 1/8 = 7/8 or 0.875 or 87.5%
No. It is 1/2.
It is (1/2)3 = 1/8
Assuming it is a fair coin, the probability is 1/24 = 1/16.
The probability of tossing two coins that are different is 1 in 2, or 0.5.The probability of tossing something on the first coin is 1. The probability of not matching that on the second coin is 0.5. Multiply 1 and 0.5 together, and you get 0.5.