Possible outcomes are HH, HT, TH, TT; therefore the probability of HH is 1/4 or 0.25.
Your question is a bit difficult to understand. I will rephrase it as follows: What is the probability of getting a head if a coin is flipped once? p = 0.5 What is the probability of getting 2 heads if a coin is flipped twice = The possible events are HT, TH, HH, TT amd all are equally likely. So the probability of HH is 0.25. What is the probability of getting at least on head if the coin is flipped twice. Of the possible events listed above, HT, TH and HH would satisfy the condition of one or more heads, so the probability is 3 x 0.25 = 0.75 or 3/4. Also, since the probability of TT is 0.25, and the probability of all events must sum to 1, then we calculate the probability of one or more heads to be 1-0.25 = 0.75
The probability of tossing a coin and getting heads is 0.5
It depends. If it's a heterozygous cross, (Tt x Tt), there's a 25% chance. If it's a homozygous dominant cross (TT x TT), the chance is 0%. Neither parent has the alleles for a recessive trait, so none of their offspring can have the recessive trait. If it's a homozygous recessive cross (tt x tt), there's a 100% chance. The only alleles the parents can pass on are recessive.
Probability of getting a head or tail is not equal
By tossing two coins the possible outcomes are:H & HH & TT & HT & TThus the probability of getting exactly 1 head is 2 out 4 or 50%. If the question was what is the probability of getting at least 1 head then the probability is 3 out of 4 or 75%
Possible outcomes are HH, HT, TH, TT; therefore the probability of HH is 1/4 or 0.25.
No, the possible results of two coin flips are; HH HT TH TT The probability of getting exactly one tail is 1/2 or 50%.
Your question is a bit difficult to understand. I will rephrase it as follows: What is the probability of getting a head if a coin is flipped once? p = 0.5 What is the probability of getting 2 heads if a coin is flipped twice = The possible events are HT, TH, HH, TT amd all are equally likely. So the probability of HH is 0.25. What is the probability of getting at least on head if the coin is flipped twice. Of the possible events listed above, HT, TH and HH would satisfy the condition of one or more heads, so the probability is 3 x 0.25 = 0.75 or 3/4. Also, since the probability of TT is 0.25, and the probability of all events must sum to 1, then we calculate the probability of one or more heads to be 1-0.25 = 0.75
The probability that an F2 plant will be tall is 3/4, based on Mendel's law of segregation and the principle of dominance.
No it is not. Sample space is: H,H & H,T & T,H & TT. As you can see, the probability of H,H is 1/4 and the probability of a H & T is 1/2.
Sample space for two coins tossed is: HH HT TH TT Therefore at most one head is HT TH TT or 3/4 or 0.75.
There is a 25% chance of getting a homozygous dominant TT tall plant, a 50% chance of getting a heterozygous Tt tall plant, and a 25% chance of getting a homozygous recessive tt short plant.
0
This depends entirely on the genotype of the parents. The probability of getting a specific genotype is the probability of getting the correct allele from mother (1/2) multiplied by the probability of getting the correct allele from father (1/2) multiplied by the number of ways this can occur. The probability of getting a phenotype, if the phenotype is dominant, is the sum of the probability of getting two dominant alleles, and the probability of getting one dominant allele. If the phenotype is recessive, the probability is equal to the probability of getting two recessive alleles.
In a single toss? zero. In two tosses, well that's a different question. Possible combinations are TT, HT, TH and HH, of which 2 of the 4 are one head and one tail. So probability is 0.50 in two tosses.
There is no probability. Sorry.