It depends. If it's a heterozygous cross, (Tt x Tt), there's a 25% chance. If it's a homozygous dominant cross (TT x TT), the chance is 0%. Neither parent has the alleles for a recessive trait, so none of their offspring can have the recessive trait. If it's a homozygous recessive cross (tt x tt), there's a 100% chance. The only alleles the parents can pass on are recessive.
well, it depends on the genes of the parents
Given those conditions, the offspring have a 50% chance of demonstrating the dominant phenotype and a 50% chance of demonstrating the recessive phenotype.
Let's see what combinations can be formed.HH, HH, Hh, Hh.So, yes their offspring can contain the recessive allele.(THe offspring can be a carrier of the recessive allele.)However, since it is impossible for the offspring to be homozygous recessive,the recessive trait/gene will not show in the offspring's phenotype.Hope that helps!
The homozygous dominant individual can only pass on the dominant allele and the homozygous recessive individual can only pass on the recessive allele, therefore all offspring will be heterozygous and have the dominant phenotype.
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
well, it depends on the genes of the parents
25%
The probability of offspring for two heterozygous dogs (Aa x Aa) is 25% homozygous dominant (AA), 50% heterozygous (Aa), and 25% homozygous recessive (aa) based on Mendelian genetics principles.
1/2 or 50%. The homozygous recessive gentoype contains two recessive alleles for the gene for a trait. So the homozygous recessive individual can pass on only recessive alleles to an offspring. The heterozygous individual has one dominant and one recessive allele for the gene for a trait. So the heterozygous individual can pass on either a dominant or a recessive allele to an offspring. So if an offspring inherits a recessive allele from the heterozygous parent, along with the recessive allele from the homozygous recessive parent, it will have the homozygous recessive genotype and phenotype.
Given those conditions, the offspring have a 50% chance of demonstrating the dominant phenotype and a 50% chance of demonstrating the recessive phenotype.
If the individual heterozygous for a cleft chin mates with an individual homozygous for chin without a cleft, their offspring can inherit their recessive allele for chin without a cleft. This would make their offspring homozygous recessive for chin without a cleft. The probability of this occurring is 50%.
The probability of a homozygous recessive offspring resulting from a cross between two homozygous dominant individuals is 0%. This is because both parents can only pass on dominant alleles, so there is no possibility of a recessive allele being passed to the offspring.
A test cross between a homozygous recessive and a heterozygous individual will yield 50% of offspring as homozygous recessive. This is because all the offspring will inherit one recessive allele from the homozygous recessive parent.
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.
If one parent is homozygous dominant (AA) and the other parent is homozygous recessive (aa), all offspring will inherit one dominant allele and display the dominant phenotype. Therefore, the probability of their offspring exhibiting the dominant phenotype is 100%.
If one parent is homozygous recessive for a trait, all of their offspring will inherit one copy of the recessive allele. Therefore, 100% of the offspring will inherit the recessive allele from a homozygous recessive parent.