There is a 4 in 6 (or 2 in 3) probability of rolling a number less than a five on a standard number cube.
The probability of an event is the number of favourable outcomes divided by the total number of possible outcomes. What is the total number of possible outcomes of tossing a number cube? 6 How many outcomes are favourable to the event of getting a five? 1 So the prob is 1/6 or 0.16667
It is a certainty - if you select enough cards.
It is 1/6.
Rolling the dice once will result in any one of the six numbers having the same probability of being up. The probability of getting a '5' = 1/6, the same as getting a '1.' ============================
The probability of getting five tails in a row is 1/2^5, or 1 in 32.The probability of getting five heads in a row is 1/2^5, or 1 in 32.Thus, the probability of getting either five heads or five tails in five tosses is 1 in 16.(The caret symbol means "to the power of," as in 2^5 means "2 to the 5th power.")
The probability is 0.0322
The probability will depend on how much you know and the extent of guessing.
00
it depends on how many numbers are on the number cube. if it only goes to 6, then the probability is 1/6. if it goes to 8 then the probability is 2/8. and so on and so on...
There is a 4 in 6 (or 2 in 3) probability of rolling a number less than a five on a standard number cube.
The answer depends on the number of choices available for each question.
The probability of getting five heads out of 10 tosses is the same as the probablity of getting five tales out of ten tosses. One. It will happen. When this happens, you will get zero information. In other words, this is the expected result.
The probability of rolling the same number on five dice is (1/6)4, or about 0.0007716.
I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.
The probability of an event is the number of favourable outcomes divided by the total number of possible outcomes. What is the total number of possible outcomes of tossing a number cube? 6 How many outcomes are favourable to the event of getting a five? 1 So the prob is 1/6 or 0.16667
The answer depends on how many cards are drawn.