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If the first roll is a three, it's impossible to get an eleven (the highest you can get is a 9), so the probability is 0. The way to get a sum of 7 is to add 3 and 4. The probability of getting a 4 on the second die is 1/6. Therefore, by adding the two probabilities of the outcomes (0 and 1/6), you get the answer: 1/6.

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Q: What is the probability of getting a sum of 7 or 11 by rolling two dice if the first roll is a 3?
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