In a large enough number of tosses, it is a certainty (probability = 1). In only the first three tosses, it is (0.5)3 = 0.125
It is 93/256 = 0.363 approx.
The probability is 0.09766%.Each toss has a ½ chance to be heads. To combine probabilities use multiply them. So the probability to get two heads out of two tosses is ½ * ½, and three heads out of three tosses is ½ * ½ * ½. So the exact answer is 0.5^10
The number of total outcomes on 3 tosses for a coin is 2 3, or 8. Since only 1 outcome is H, H, H, the probability of heads on three consecutive tosses of a coin is 1/8.
It is 3/8.
33%
0.53 = 0.125.
In a large enough number of tosses, it is a certainty (probability = 1). In only the first three tosses, it is (0.5)3 = 0.125
It is 93/256 = 0.363 approx.
The probability is 0.09766%.Each toss has a ½ chance to be heads. To combine probabilities use multiply them. So the probability to get two heads out of two tosses is ½ * ½, and three heads out of three tosses is ½ * ½ * ½. So the exact answer is 0.5^10
The probability of getting heads on three tosses of a coin is 0.125. Each head has a probability of 0.5. Since the events are sequentially unrelated, simply raise 0.5 to the power of the number of tosses (3) and get 0.125, or 1 in 8.
The probability is 0.0322
The number of total outcomes on 3 tosses for a coin is 2 3, or 8. Since only 1 outcome is H, H, H, the probability of heads on three consecutive tosses of a coin is 1/8.
It is 3/8.
If you toss the die often enough then the probability of getting the sequence 2-2-1 is 1: a certainty. The probability of getting the result in the first three tosses is 1/216.
The opposite of getting at most two heads is getting three heads. The probability of getting three heads is (1/2)^2, which is 1/8. The probability of getting at most two heads is then 1 - 1/8 which is 7/8.
Pr(At least one head in three tosses) = 1 - Pr(No heads in three tosses) = 1 - Pr(Three tails in three tosses) = 1 - (1/2)*(1/2)*(1/2) = 1 - 1/8 = 7/8 or 0.875 or 87.5%