The probability is zero! There is no such thing as "normal". Every child (and adult) has some unique characteristics and that makes them not normal - in that respect.
Nowadays it is approximately 0.5169
It's used commonly to estimate the traits of a child of two parents. For example, the probability of the child having blue eyes, or curly hair, or even having genetic disease.
Since having a child to a child is an independent event (assuming no outside intervention), the probability is still about 50 / 50 boy or girl.
The probability of having a blue-eyed child depends on the genetic makeup of the parents. If both parents carry the recessive allele for blue eyes (Bb), where "B" represents the brown eye allele and "b" represents the blue eye allele, there is a 25% chance of having a blue-eyed child (bb). If one or both parents have brown eyes but carry the blue eye allele, the probability may vary. If neither parent has the blue eye allele, the probability of having a blue-eyed child is 0%.
Make a punnet square with the mother above, her genotype would be: X^B X^b, and the father to the left whose genotype is X^b Y.The probability of having a colorblind CHILD is 50%. The probability of them having a SON is 50%. Since we are asked what the probability of their SON being colorblind, it is 50% as well. The reason is because the chance of having a colorblind son, among sons only, (according to the punnet square) is 50%.
0.1%
Nowadays it is approximately 0.5169
It's used commonly to estimate the traits of a child of two parents. For example, the probability of the child having blue eyes, or curly hair, or even having genetic disease.
Divorce is a complicating factor in the life of a child, but the child will adapt, and in all probability will have a normal future.
Since having a child to a child is an independent event (assuming no outside intervention), the probability is still about 50 / 50 boy or girl.
It is always 50/50.
The probability of having a blue-eyed child depends on the genetic makeup of the parents. If both parents carry the recessive allele for blue eyes (Bb), where "B" represents the brown eye allele and "b" represents the blue eye allele, there is a 25% chance of having a blue-eyed child (bb). If one or both parents have brown eyes but carry the blue eye allele, the probability may vary. If neither parent has the blue eye allele, the probability of having a blue-eyed child is 0%.
1/4
Make a punnet square with the mother above, her genotype would be: X^B X^b, and the father to the left whose genotype is X^b Y.The probability of having a colorblind CHILD is 50%. The probability of them having a SON is 50%. Since we are asked what the probability of their SON being colorblind, it is 50% as well. The reason is because the chance of having a colorblind son, among sons only, (according to the punnet square) is 50%.
1/2
1/32
In this scenario, the mother is heterozygous for normal skin pigmentation (Aa) and the father is homozygous recessive for albinism (aa). The possible genotypes for their child are Aa (normal pigmentation) and aa (albino). Using a Punnett square, there is a 50% probability that the child will be albino (aa).